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DochEvi [55]
3 years ago
12

After completing an experiment, all chemical wastes should be an disposed of according to your instructor’s directions. be left

at your lab station for the next class. c dumped in the sink. d taken home.
Chemistry
1 answer:
Arturiano [62]3 years ago
7 0

Answer:1

Explanation:

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Answer:

its either A or D

H0p3 th1$ H3lp$

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What is the molecular weight of H3PO4
olga2289 [7]
H = 1 amu
P =  31 amu
O = 16 amu

Therefore:

H3PO4 = 1 x 3 + 31 + 16 x 4 => 98 u

hope this helps!
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What is the difference between 2 ml of salt and 2.0 ml of salt?
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3 years ago
​29. A gas has a volume of 1.75 L at -23°C and 150.0 kPa.
arsen [322]

The answer for the following mention bellow.

  • <u><em>Therefore the final temperature of the gas is 260 k</em></u>

Explanation:

Given:

Initial pressure (P_{1}) = 150.0 kPa

Final pressure (P_{2}) = 210.0 kPa

Initial volume (V_{1}) = 1.75 L

Final volume (V_{2}) = 1.30 L

Initial temperature (T_{1}) = -23°C = 250 k

To find:

Final temperature (T_{2})

We know;

According to the ideal gas equation;

P × V = n × R ×T

where;

P represents the pressure of the gas

V represents the volume of the gas

n represents the no of moles of the gas

R represents the universal gas  constant

T represents the temperature of the gas

We know;

\frac{P*V}{T} = constant

\frac{P_{1} }{P_{2} } × \frac{V_{1} }{V_{2} } = \frac{T_{1} }{T_{2} }

Where;

(P_{1}) represents the initial pressure of the gas

(P_{2}) represents the final pressure of the gas

(V_{1}) represents the initial volume of the gas

(V_{2}) represents the final volume of the gas

(T_{1}) represents the initial temperature of the gas

(T_{2}) represents the final temperature of the gas

So;

\frac{150 * 1.75}{210 * 1.30} = \frac{260}{T_{2} }

(T_{2}) =260 k

<u><em>Therefore the final temperature of the gas is 260 k</em></u>

<u><em></em></u>

3 0
3 years ago
How many Oxygen atoms in: 5H2SO3
astra-53 [7]

Answer:

20

Explanation: I think

5 0
3 years ago
Read 2 more answers
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