Givens
<em><u>Slower car</u></em>
r = r
t = 12 hours
d = ?
<em><u>Faster car</u></em>
r = r + 20
t = 8 hours
d = ?
It doesn't matter what the exact distance is. You just have to know that the 2 distances are equal ie going to the mountains from his home is the same distance as going from the mountains to his home.
d = r * t
r * 12 hours = (r + 20)* 8 hours. Remove the brackets on the right
r*12 = 8r + 20*8
r*12 = 8*r + 160
r*12 - 8r = 8r - 8r + 160
4r = 160
r = 40 miles / hour
=================
Slower Ride determines the distance.
d = r*t
d = 40 * 12
d = 480
Check
Use the faster rate (r + 20) = 40 + 20 = 60 mph
60 * 8 = 480. Both distances work out to be the same.
139 + 30d = 13 + 51d
139 - 13 = 51d - 30d
126 = 21d
126/21 = d
6 = d
now lets check..
139 + 30d = 139 + 30(6) = 319
13 + 51d = 13 + 51(6) = 319
so on day 6, they will both cost $ 319
Answer:
30 AND 40
Step-by-step explanation:
SUM OF RATIO IS 4 + 3 = 7
1ST NUMBER : 4/7 × 70 = 40
2ND NUMBER : 3/7 × 70 = 30
Answer:
a=28m^2
Step-by-step explanation:
Given:
l=14m
w=200cm
Required
a=?
w in meters
Formula:
1m=100cm
b=200cm---criss cross it
b*100cm/100cm=1m*200cm/100cm
b=2m
a=l*w
a=14m*2m
a=28m^2
