Help please Due in 5 mins I really need help!!!!!!!!!!!!!!
2 answers:
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Use cosine law to solve the problem. See image attached.
What we're looking for is the length of side A (a side which is opposite with angle A).
This is the formula of cosine law
A² = B² + C² - 2BC cos A
Input the numbers
A² = 75² + 90² - 2(75)(90) cos 85°
A =
A =
What we're looking for is the length of side A (a side which is opposite with angle A).
This is the formula of cosine law
A² = B² + C² - 2BC cos A
Input the numbers
A² = 75² + 90² - 2(75)(90) cos 85°
A =
A =
y = 11/21
To solve this first evaluate the power (then calculate the sum):
<u><em></em></u>y - <u><em>
</em></u> = 5y +<u><em> (-5 + 7)</em></u>
16y - 9 = -5y + 2
Next Move terms (move variable to the left side and change its sign) (Move constant to the right side and change its sign):
16y <u><em>- 9 </em></u>= <u><em>-5y</em></u> + 2
16y + 5y = 2 + 9
Next Collect the like terms and calculate the sum:
<u><em>16y + 5y</em></u> = <u><em>2 + 9</em></u>
21y = 11
Lastly divide both sides of the equation by 21:
<u><em>21y = 11</em></u>
y =