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wlad13 [49]
3 years ago
11

what is the surface area of a pyramid if the length and width is 10 inches and the height is 9 inches?

Mathematics
1 answer:
pav-90 [236]3 years ago
4 0
Answer is 380 inches squared. The bottom side is 10x10 which is 100, then all 4 sides are 10x7 which is 70, but you have to multiply that by 4 so it becomes 280. Then you add 280 and 100, the final answer is 380in^2
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The stock's value dropped from $38.50 to $34.00.What negative number shows the change in value?
Liula [17]
I believe that would be -4.50 for problems like this you subtract then add the negative sign in front
i'm surprised you are in high school i did this in 6th grade
7 0
3 years ago
You have 2/3 of sugar how muck sugar will you use if you makes 6 batches of cookies
zalisa [80]

Answer:

4

Step-by-step explanation:

1 batch = 2/3

so 6 batches = 2/3 * 6

and 2/3 *6 = 4 !

4 0
3 years ago
Find the area of a regular octagon with an apothem of 7 inches and a side length of 5.8 inches. (nearest tenth)
Kisachek [45]

Answer:

162.4 in²

Step-by-step explanation:

LETS GET INTOOOOEEETTT

Let's start with what we know:

Area of regular octagon = 1/2 x perimeter x apothem

We know the apothem, so all that we need to find to fill in the above equation is the perimeter:

perimeter = 8 x 5.8 = 46.4in

Now we can fill in our original equation and solve:

Area of regular octagon = 1/2 x perimeter x apothem

Formula = n (s/2)² divided by tan( π /n)

   = 8 (5.8/2)²  divided by tan ( π /8)

                 = 162.4283 in²

ORRR when rounded to the nearest tenth,

                      =162.4 in²

6 0
3 years ago
Picture attachment is below
Stolb23 [73]

Answer:

D

Step-by-step explanation:

A rational number will either end or repeat forever like the first three, but the fourth one, pi, will go on forever and never repeat, making it irrational.

5 0
3 years ago
In this line of circles, the ratio of red circles to blue circles is 1:3 How many more circles would need to be added to make th
zaharov [31]

Answer:

The number of red circles to be added would be equal to 8 times the original amount of red circles

Step-by-step explanation:

Let

x ----> the number of red circles

y ----> the number of blue circles

Originally

\frac{x}{y}=\frac{1}{3}

y=3x ----> equation A

How many more circles would need to be added to make the ratio of red to blue 3:1

Let

n ----> the  number of additional red circles

\frac{x+n}{y}=\frac{3}{1} ----> equation B

substitute equation A in equation B

\frac{x+n}{3x}=\frac{3}{1}

solve for n

x+n=9x\\n=9x-x\\n=8x

therefore

The number of red circles to be added would be equal to 8 times the original amount of red circles

5 0
3 years ago
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