To solve this you need to know Pythagorean theorem.
First, EG is 24, so the halfway points are 12. Knowing Pythagorean triples, you can use 5,12,13 and 12,16,20.
DF = 5+16
DF = 21
If you don't know Pythagorean triples, I have worked it out on the image attached.
Answer:
30
Step-by-step explanation:
Find the lowest number divisible by both 6, 5, and 2.
To start, let's list off the numbers divisible by six, and see if we can check any of them off for 5. Since both 2 and 6 are even numbers, we know that if a number is divisible by 6, it's divisible by 2.
6 12 18 24 30 36 42 48 54 60
All of these numbers are divisible by two. Let's find the lowest one that is divisible by 5. We know this by either the umber ending in 5 or 0.
30 is the lowest number that is divisible by 2, 5, or 6.
There's an app called photomath that would be useful for these kinds of problems!
Loook on google and find the answers
Answer:
<em>1690</em>
Step-by-step explanation:
V = LWH
V = 13 * 10 * 13
V = 1690
