A ball is kicked into the air and follows the path described by h(t)= – 4.9t^2 + 6t + 0.6, where t is the time in seconds and h
is the height in meters above the ground. Find the maximum height of the ball. What value would you have to change in the equation if the maximum height of the ball is more than 2.4 meters?
1 answer:
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Answer:
Regression Line is given by,
y = 22.909 + 0.209 x
The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436
Step-by-step explanation:
The equation of Regression equation is of the form of:
y = a + bx
where, a is intercept and b is slope
The formula for a and b is given by,
Here, ∑X = 1149.8, ∑Y = 377.2, ∑XY = 93115.95, ∑X² = 320246.72
Thus, a = 22.909
and b = 0.209
Thus, Regression Line is given by,
y = 22.909 + 0.209 x
Thus, The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436
Now plotting these line:
