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Mila [183]
3 years ago
6

If your correct i will give u brainlist=)

Mathematics
2 answers:
morpeh [17]3 years ago
4 0

Answer:

point m' translated down 6 units

Step-by-step explanation:

victus00 [196]3 years ago
3 0

Answer:

6M

Step-by-step explanation:

M[3,3]→M[3,-3]=3M,3M→3M,-3M

6M

AM I RIGHT

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EASY POINT!!! PLEASE HELP!!!
Lostsunrise [7]

Answer:

(-13/5,0) and (-17/5,0)

Step-by-step explanation:

(-13/5,0) and (-17/5,0) would be the x-intercepts

7 0
3 years ago
Explain how to find the distance between two integers using the difference
maksim [4K]

Answer:

Step-by-step explanation:

When we want to find the distance between two integers using the difference, the best way is to plot them on number line. And then count distance between them.

For example -3 and -1.

When we want to find difference we have:

-3-(-1)=-2

But distance can not be negative.

Now, we need to count distance between numbers -3 and -1 on the number line.

So we have from -3 to -2, one place and from -2 to -1 one place it is 2 places.

So distance is 2.

6 0
3 years ago
Read 2 more answers
5h+6y+4h+9y=3h+5y6h+9y
Leokris [45]
H=6y/5y^(6) -6

hope this helps!!!!!!!!
3 0
3 years ago
The scheduled arrival time for a daily flight from Boston to New York is 9:30 am. Historical data show that the arrival time fol
Galina-37 [17]

Answer:

Step-by-step explanation:

Let x be a random variable representing the flight arrival time from Boston to New York.

For a uniform probability distribution, the notation is

X U(a, b) where a is the lowest value of x and b is the lowest value of x

The probability density function, f(x) = 1/(b - a)

Mean, µ = (a + b)/2

Standard deviation, σ = √(b - a)²/12

From the information given, the time difference in minutes is 9:57 - 9:07 = 50 minutes. Therefore,

a = 0

b = 50

µ = (0 + 50)/2 = 25

σ = √(50 - 0)²/12 = 14.43

b) converting to minutes, it is 9:30 - 9:07 = 23 minutes

the probability that a flight arrives late(later than 9:30 am) is expressed as P(x > 23)

f(x) = 1/(50) = 0.02

P(x > 23) = (50 - 23)0.02 = 0.54

7 0
3 years ago
the maximum walking speed S, in feet per second of an animal can be modeled by the equation S=the square root gL where g=32ft/se
swat32

The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

<h3>Calculating Maximum speed</h3>

From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus

From the give information,

The maximum walking speed, S, is given by

S = √gL

Where g = 32ft/sec
and L is the length of the animal's leg

Thus,

For a Giraffe with a leg length of 6 feet

S = √32×6

S = √192

S = 13.856 ft/sec

For a Hippopotamus with a leg length of 3 feet

S = √32×3

S = √96

S = 9.798 ft/sec

Now, we will determine how many times greater 13.856 is than 9.798

13.856/9.798 = 1.41

Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

Learn more on Calculating Speed here: brainly.com/question/15784810

#SPJ1

3 0
2 years ago
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