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2 years ago

What is the binary number for 17

Mathematics

2 answers:

Vaselesa [24]2 years ago

6 0

Answer:

10001

Step-by-step explanation:

matrenka [14]2 years ago

5 0

Answer:

♡ hi there! madeline here. ♡

- your answer is 10001

also, since I answered first, can I get the brainliest?

thank you, have a great day sandra!

✧･ﾟ: *✧･ﾟ:･ﾟ✧*:･ﾟ✧･ﾟ: *✧･ﾟ:･ﾟ✧*:･ﾟ✧

Step-by-step explanation:

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Help me i don't understand the problem

Mashutka [201]

The question is asking you to find out what number is a fraction of something. For example, the problem on the top right is asking 35 is 50% (one half) of a number so what you have to do is multiply 35 times 2 and the answer is 70

5 0

3 years ago

Nine hundred ninety two hundred thousandths wrote in decimal form

uranmaximum [27]

Answer:

I think the answer is 9.920 please be careful with your answer I think it 9.920 because it says nine hundred and ninety two thousands so therefor the decimal need to be in between 9 and 9 I hope you get this correct!

step-by-step explanation:

3 0

2 years ago

Write a polynomial of least degree with rational coefficients, a leading coefficient of 1, and zeros at 3 and sqr root 7. Expand

Tresset [83]

Answer:

(x-3)(x^2-7) = x^3 -3x^2 -7x + 21

just change the sign of the root and put x in front of it, then multiply the factors all together

(x-3)(x-sqr7)(x+sqr7) roots come in conjugate pairs to eliminate irrational coefficients

(x-sqr7)(x+sqr7) = x^2-7. similar to (a-b)(a+b) = a^2-b^2

Step-by-step explanation:

6 0

3 years ago

Arrange the steps to solve the equation square root x+3 - square root 2x-1=-2

stiv31 [10]

Answer:x=31.4919

Step-by-step explanation:

Step1:isolate a square root on the left hand side√x+3=√2x-1-2

Step2:eliminate the radicals on the left hand side

Raise both sides to the second power

√x+3)^2=(√2x-1-2)^2

After squaring

x+3=2x-1+4-4-4√2x-1

Step3:get the remaining radicals by itself

x+3=2x-1+4-4√2x-1

Isolate radical on the left hand side

4√2x-1=-x-3+2x-1+4

4√2x-1=x

Step4:eliminate the radicals on the left hand side

Raise both side to the second power

(4√2x-1)^2=x^2

After squaring

32x-16=x^2

Step 5:solve the quadratic equation

x^2-32x-16

This equation has two real roots

x1=32+√960/2=31.4919

x2=32-√960/2=0.5081

Step6:check that the first solution is correct

Put in 31.4919 for x

√31.4919+3=√2•31.4919-1-2

√34.492=5.873

x=31.4919

Step7:check that the second solution is correct

√x+3=√2x-1-2

Put in 0.5081 for x

√0.5081+3=√2•0.5081-1-2

√3.508=-1.873

1.873#-1.873

One solution was found

x=31.4919

6 0

3 years ago

Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

3 0

3 years ago

What is the binary number for 17​

What is the binary number for 17