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3 years ago

De acuerdo con la siguiente función f(x)=-3x+8, ¿cuál es el punto de intersección de su grafica con el eje y?

Mathematics

1 answer:

Ket [755]3 years ago

4 0

Answer:

El punto de intersección con el eje “y” será (0 ; 8).

Step-by-step explanation:

En este caso la función es f(x)= -3*x + 8, o lo que es lo mismo, y= -3*x + 8

Para encontrar la intersección en y, se debe sustituir a la variable x por 0 por en la función. Una vez hecha la sustitución, es posible resolver la ecuación para encontrar el valor de y.

En este caso:

y= -3*0 + 8

Resolviendo:

y= 0 + 8

y= 8

Otra forma de resolverlo es, siendo la función f(x)= m*x + b (donde m es la pendiente y b la ordenada al origen), el valor b es el punto donde una recta cruza el eje y. En este caso la ordenada al origen tiene un valor de 8.

Entonces el punto de intersección con el eje “y” será (0 ; 8).

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3 years ago

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Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati

Margaret [11]

Answer:

1. The minimum head breadth that will fit the clientele is of 4.41-in.

2. The maximum head breadth that will fit the clientele is of 7.19-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 5.8-in and a standard deviation of 0.8-in.

This means that $\mu = 5.8, \sigma = 0.8$

1. What is the minimum head breadth that will fit the clientele?

The 4.1st percentile, that is, X when Z has a pvalue of 0.041, so X when Z = -1.74.

$Z = \frac{X - \mu}{\sigma}$

$-1.74 = \frac{X - 5.8}{0.8}$

$X - 5.8 = -1.74*0.8$

$X = 4.41$

The minimum head breadth that will fit the clientele is of 4.41-in.

2. What is the maximum head breadth that will fit the clientele?

100 - 4.1 = 95.9th percentile, that is, X when Z has a pvalue of 0.959, so X when Z = 1.74.

$Z = \frac{X - \mu}{\sigma}$

$1.74 = \frac{X - 5.8}{0.8}$

$X - 5.8 = 1.74*0.8$

$X = 7.19$

The maximum head breadth that will fit the clientele is of 7.19-in.

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3 years ago

Determine the approximate value of a. 18.11 7.05 7.95 9.71

Alex777 [14]

Answer:

7.95

Step-by-step explanation:

In order to solve this, we need to use the rule of sine which is (a/sinA)=(b/sinB)=(c/sinC). Since we have both values of c we can do (12/sin104), which equals ~12.37. Therefore, since we already have A, 12.37=(a/sin40). We can change this by doing sin40×12.37=a. sin40×12.37=7.95.

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3 years ago

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4 years ago

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Yuki888 [10]

Answer:

total population of school = 1000

1000 - 450 males = 550 female students

550 - 200 females not in extra curriculars = 350 females in extra curriculars

350 + 90 males in extra curriculars = 440 total in extra curriculars

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Circle B - overlap = 200 females not in extra curriculars

440 + 200 = 640

1000 - 640 = 370 students represented by the portion of the Venn diagram not in either circle

Step-by-step explanation:

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