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topjm [15]
3 years ago
7

To make green paint students mixed yellow paint with blue paint the table below shows how many yellow and blue drops from a drop

per several students used to make the same shade of green paint :help
Mathematics
1 answer:
Airida [17]3 years ago
7 0

Answer:

ans is 7

hope it helps !

...

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Can someone please help me with this question?? It’s really hard and once you understand it, can you please give me an explanati
Thepotemich [5.8K]

We want to subtract 8x + 3 from -2x+5. We can create an expression to represent this.

-2x + 5 - (8x + 3).


After this, lets distribute the - sign (think of this like expanding something with -1).

-2x + 5 - 8x - 3


Lastly, we just need to combine like terms.

-2x + 5 - 8x - 3


Combine the 5 and -3 to get 2.

-2x + 2 - 8x


Combine the -2x and -8x to get -10x.

-10x + 2


The final answer to the question is therefore A.

3 0
3 years ago
I WAS ONLY ABLE TO SELECT 40 PTS THIS TIME, PLS ANSWER THIS ONE IT HAS THE PICTURE WITH IT.
BaLLatris [955]
Okay so the first one is right.
The second one is wrong.
the third one is right.
The forth one is wrong.
4 0
3 years ago
Read 2 more answers
Is -(12/-17) equal to 12/17
maria [59]
Yes <span>-(12/-17) is equal to 12/17

I hope this helps. 

Have a awesome day. :)</span>
3 0
3 years ago
What is lim x→-3 sqrt x^2-8
vitfil [10]

If the  -8 is under the square root, then...

\displaystyle L = \lim_{x\to -3} \sqrt{x^2-8}\\\\L = \sqrt{(-3)^2-8}\\\\L = \sqrt{9-8}\\\\L = \sqrt{1}\\\\L = 1\\\\

OR

If the -8 is not under the square root, then...

\displaystyle L = \lim_{x\to -3} \sqrt{x^2}-8\\\\L = \sqrt{(-3)^2}-8\\\\L = \sqrt{9}-8\\\\L = 3-8\\\\L = -5

Either way, we replace x with -3 and simplify.

For more information, refer to the direct substitution rule for limits.

4 0
1 year ago
Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k
ch4aika [34]

Given

\vec v =  f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k

the curl of \vec v is

\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

7 0
3 years ago
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