I wrote that wrong, sorry.
1/4= 0.25%
25%>0.25
So, 25% of 80 is more than 1/4% of 80 and 1/4% of 80 is less than 25% of 80.
The third one is the answer?
This question is Incomplete
Complete Question
What sample size is needed to give a margin of error within ± 13 in estimating a population mean with 99% confidence, assuming a previous sample had s=116
Answer:
The sample size n = 530 samples
Step-by-step explanation:
Margin of Error formula = z × standard deviation/√n
Margin of Error = ± 13
Standard deviation = 116
z = z score of 99% = 2.58
±13 = 2.58 × 116/√n
Cross Multiply
±13 × √n = 2.58× 116
±13 × √n = 299.28
√n = 299.28/±13
√n = ± 23.0215384615
Square both sides
(√n)² = (±23.0215384615)²
n = 529.991233134
Approximately , n = 530 samples
Answer: x= 17 I hope that helps you understand it Goodbye!
Step-by-step explanation:
7(x-2)=5(x+4) So the first step is to Distribute meaning Multiply so 7(x-2 ) that would give you -14 that where I got that from and I just did 5(x+4)= 20 and bring the x down
1. 7x-14=5x+20 So, I just do the opposite of subtracting which is adding so, I'm going to add 14 to both sides
2. 7x=5x+20+14 = 5x+34
3. 7x= 5x+34 So, I'm going to do the opposite of adding now which is subtracting meaning I'm just going to subtract 5x from both sides
4. 7x-5x=34 So then I do 7x-5x=2x
5. 2x= 34 so. I just Divide 2 from both sides x=34/2= 17
So, your answer would be x=17 and yes you got to put the variable for your answer to be right you can't just put 17 it got to be x= 17 and variable is just letters in the equation don't let it confused you but that would be your answer x=17 And can you make me Brainliest Please
