Ask question

Ask question

All categories

2 years ago

5

Todd has at most 14 dimes and nickels in his pocket and the total value of the coins is more than $1. If x represents the number

of dimes and y represents the number of nickels which system of inequalities can be used to determine how many of each coin todd has in his pocket.

1 answer:

sattari [20]2 years ago

5 0

Answer:

x+y≤14

10x+5y>100

Step-by-step explanation:

Got it right! Hope this helps!

You might be interested in

What is the probability of spinning the pointer on the spinner below and getting a 2 or 4

Lubov Fominskaja [6]

Answer:

The probability would be 2/5

Step-by-step explanation:

There is five numbers on the spinning and the chance of getting one certain number would be 1/5, and if you add the two probabilities together would be 2/5, I am pretty sure.

3 0

2 years ago

Solve for x.<br><br> PLEASE HELP!!

cricket20 [7]

Answer:

i dont know

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

-9/11 multiplied by -11/9

Sunny_sXe [5.5K]

99/99= 1
(Mark me the brainliest)

4 0

2 years ago

Which calculation will ALWAYS give a result greater than 1? A.5 × a number less than 1 B.4/9+ a fraction less than 12 C. 1 3/4 -

Bas_tet [7]

Answer:

C. 1 3/4 - (a fraction less than 3/4)

Step-by-step explanation:

Your number sense should be able to help you with this one.

A. 5 × 1/10 = 1/2, not a number greater than 1

B. 4/9 + 1/3 = 7/9, not a number greater than 1

C. 1 3/4 -1/2 = 1 1/4, a number greater than 1 (see below for more explanation)

D. 7/8 × 1/2 = 7/16, not a number greater than 1.

__

<em>More explanation</em>

Let x represent a number less than 3/4. Then we want to make sure that ...

y = 1 3/4 - x

will be greater than 1.

Solving for x, we get ...

x = 1 3/4 - y

Applying the requirement that x < 3/4, we have ...

x < 3/4

(1 3/4 -y) < 3/4

1 3/4 < y + 3/4 . . . . . . add y

1 < y . . . . . . . . . . . . . . .subtract 3/4

We see that the condition on x makes sure that y is always greater than 1.

3 0

3 years ago

A researcher wants to estimate the percentage of all adults that have used the Internet to seek pre-purchase information in the

Lubov Fominskaja [6]

Answer:

The required sample size for the new study is 801.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

25% of all adults had used the Internet for such a purpose

This means that $\pi = 0.25$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

What is the required sample size for the new study?

This is n for which M = 0.03. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.25*0.75)}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.25*0.75}$

$\sqrt{n} = \frac{1.96\sqrt{0.25*0.75}}{0.03}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.25*0.75}}{0.03})^2$

$n = 800.3$

Rounding up:

The required sample size for the new study is 801.

4 0

2 years ago