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Amiraneli [1.4K]

3 years ago

10

A baker has 6 small bags of flour. Each bag weighs 1 pound. She divides each bag into thirds. How many 1/3 - pound bags of flour

does the baker have? Show your work. Simplify if necessary.

1 answer:

lana [24]3 years ago

5 0

Answer:

18 smaller bags

Step-by-step explanation:

Each one pound bag becomes 3 one-third pound bags.

So 6 one pound bags will become 6×3=18 one-third pound bags.

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Help me with this plz.

kondaur [170]

The answer is F because my brother is in high school and he knows the's things

7 0

3 years ago

Read 2 more answers

Carson purchased supplies for his computer for $64. The sales tax was $4.16. He gave the salesperson $80. How much change did he

krek1111 [17]

To work this out you need to do 80 - 64 - 4.16 = 11.48

he received $11.48 change

3 0

3 years ago

F(x) = x + 4 and g(x) = 2x + 3, evaluate each expression.

Rom4ik [11]

Answer:

$15.~f(g(2))=\Large\boxed{11}\\$

$16.~g(f(2.5))=\Large\boxed{16}$

$17.~g(f(-5))=\Large\boxed{1}$

$18.~f(g(-5))=\Large\boxed{-3}$

Step-by-step explanation:

<h3>Given information</h3>

$f(x)=x+4$

$g(x)=2x+3$

<h3>Question 15. f(g(2))</h3>

<u>Substitute values into the first function</u>

$g(2)=2(2)+3$

$g(2)=4+3$

$g(2)=7$

<u>Substitute the values of the first function into the second</u>

$f(g(2))=f(7)$

$f(7)=(7)+4$

$f(7)=\Large\boxed{11}$

<h3>Question 16. g(f(2.5))</h3>

<u>Substitute values into the first function</u>

$f(2.5)=(2.5)+4$

$f(2.5)=6.5$

<u />

<u>Substitute the values of the first function into the second</u>

$g(f(2.5))=g(6.5)$

$g(6.5)=2(6.5)+3$

$g(6.5)=13+3$

$g(6.5)=\Large\boxed{16}$

<h3>Question 17. g(f(-5))</h3>

<u>Substitute values into the first function</u>

$f(-5)=(-5)+4$

$f(-5)=-1$

<u>Substitute the values of the first function into the second</u>

$g(f(-5))=g(-1)$

$g(-1)=2(-1)+3$

$g(-1)=-2+3$

$g(-1)=\Large\boxed{1}$

<h3>Question 18. f(g(-5))</h3>

<u>Substitute values into the first function</u>

$g(-5)=2(-5)+3$

$g(-5)=-10+3$

$g(-5)=-7$

<u>Substitute the values of the first function into the second</u>

$f(g(-5))=f(-7)$

$f(-7)=(-7)+4$

$f(-7)=\Large\boxed{-3}$

Hope this helps!! :)

Please let me know if you have any questions

7 0

1 year ago

What is the integral of ∫4x^2 dx

Nataly_w [17]

Answer:

$\boxed{\frac{4}{3} x^3 + c}$

Step-by-step explanation:

$\int\limits {4x^2} \ dx$

$= \frac{4}{3} x^3 + c$

5 0

3 years ago

Read 2 more answers

Evaluate the function at each specified value of the independent variable and simplify. (if an answer is undefined, enter undefi

tekilochka [14]

For this case we have the following function:

$h (t) = t ^ 2 - 8t$

What we should do is evaluate the function for the different values of the independent variable.

We have then:

For x = 8:

$h (8) = (8) ^ 2 - 8 (8)$

$h (8) = 64 - 64$

$h (8) = 0$

For x = 1.8:

$h (1.8) = (1.8) ^ 2 - 8 (1.8)$

$h (1.8) = 3.24 - 14.4$

$h (1.8) = -11.16$

For x = x + 8:

$h (x + 8) = (x + 8) ^ 2 - 8 (x + 8)$

$h (x + 8) = x ^ 2 + 16x + 64-8x-64$

$h (x + 8) = x ^ 2 + 18x$

Answer:

The results of evaluating the function are:

$h (8) = 0$

$h (1.8) = -11.16$

$h (x + 8) = x ^ 2 + 18x$

5 0

3 years ago