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vovikov84 [41]
4 years ago
6

How many solutions does the equation have? 4(z−5)+2=4z−18

Mathematics
2 answers:
ANTONII [103]4 years ago
7 0
Distribute the 4:
4z - 20 + 2 = 4z - 18
Subtract 4z
-20 + 2 = -18
-18 = -18
This is true so that means there are infinite number of solutions... z could be anything!
ad-work [718]4 years ago
7 0
All real numbers is the solution of this equation

4z - 20 +2 = 4z - 18

4z - 18  = 4z - 18
      +18         +18

4z = 4z 


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