How many solutions does the equation have?
4(z−5)+2=4z−18
2 answers:
Distribute the 4: 4z - 20 + 2 = 4z - 18 Subtract 4z -20 + 2 = -18 -18 = -18 This is true so that means there are infinite number of solutions... z could be anything!
All real numbers is the solution of this equation 4z - 20 +2 = 4z - 18 4z - 18 = 4z - 18 +18 +18 4z = 4z
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Step-by-step explanation:
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