This question is in reverse (in two ways):
<span>1. The definition of an additive inverse of a number is precisely that which, when added to the number, will give a sum of zero. </span>
<span>The real problem, in certain fields, is usually to show that for all numbers in that field, there exists an additive inverse. </span>
<span>Therefore, if you tell me that you have a number, and its additive inverse, and you plan to add them together, then I can tell you in advance that the sum MUST be zero. </span>
<span>2. In your question, you use the word "difference", which does not work (unless the number is zero - 0 is an integer AND a rational number, and its additive inverse is -0 which is the same as 0 - the difference would be 0 - -0 = 0). </span>
<span>For example, given the number 3, and its additive inverse -3, if you add them, you get zero: </span>
<span>3 + (-3) = 0 </span>
<span>However, their "difference" will be 6 (or -6, depending which way you do the difference): </span>
<span>3 - (-3) = 6 </span>
<span>-3 - 3 = -6 </span>
<span>(because -3 is a number in the integers, then it has an additive inverse, also in the integers, of +3). </span>
<span>--- </span>
<span>A rational number is simply a number that can be expressed as the "ratio" of two integers. For example, the number 4/7 is the ratio of "four to seven". </span>
<span>It can be written as an endless decimal expansion </span>
<span>0.571428571428571428....(forever), but that does not change its nature, because it CAN be written as a ratio, it is "rational". </span>
<span>Integers are rational numbers as well (because you can always write 3/1, the ratio of 3 to 1, to express the integer we call "3") </span>
<span>The additive inverse of a rational number, written as a ratio, is found by simply flipping the sign of the numerator (top) </span>
<span>The additive inverse of 4/7 is -4/7 </span>
<span>and if you ADD those two numbers together, you get zero (as per the definition of "additive inverse") </span>
<span>(4/7) + (-4/7) = 0/7 = 0 </span>
<span>If you need to "prove" it, you begin by the existence of additive inverses in the integers. </span>
<span>ALL integers each have an additive inverse. </span>
<span>For example, the additive inverse of 4 is -4 </span>
<span>Next, show that this (in the integers) can be applied to the rationals in this manner: </span>
<span>(4/7) + (-4/7) = ? </span>
<span>common denominator, therefore you can factor out the denominator: </span>
<span>(4 + -4)/7 = ? </span>
<span>Inside the bracket is the sum of an integer with its additive inverse, therefore the sum is zero </span>
<span>(0)/7 = 0/7 = 0 </span>
<span>Since this is true for ALL integers, then it must also be true for ALL rational numbers.</span>
Answer:
706.86ft²
Step-by-step explanation:
A=πr2=π·152≈706.85835ft²
please make me Brainliest
<h3>G I V E N : </h3>
A man is paid $1500 salary. He spends 20% of the salary for his kids education, 35% for food, 15% for miscellaneous and he saves the rest. How much money does he save?
<h3>S O L U T I O N : </h3>
Total Income = $ 1500
According to the question,
He spends 20% to his kids education
He spends 35% for food
He spends 15% for miscellaneous
Out of total income he spends 20% on kids education
So, amount spent on kids education = 20% of $1500
Amount = 20/100 × $1500
Amount = $300
Hence, money spent on his kids education is $300
35% is spent on food
Money spent on food = 35% of $1500
Money spent = 35/100 × $1500
Money spent = $525
Hence, money spent on food is $525
15% is spent on miscellaneous
Money spent on miscellaneous = 15% of $1500
Money spent = 15/100 × $1500
Money spent = $225
Hence, money spent on miscellaneous is $225
Now, adding all the three we get
$300 + $525 + $225
$825 + $225
$1050
Total money spent = $1050
Remaining money = $1500 - $1050 = $450
- <u>Remaining amount left with him is $450</u>
Answer:
12
Step-by-step explanation:
The common ratio is 1.5. If the input is 8, the output has to be 12.
Hi There!
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Problem #1:
At the dealership where she works, Sade fulfilled 3/10 of her quarterly sales goal in January and another 1/10 of her sales goal in February. What fraction of her quarterly sales goal had Sade reached by the end of February?
3/10 + 1/10 = 4/10
4/10 of her goal.
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Problem #2:
Shane has been monitoring his mileage. According to last week's driving log, he drove 1/10 of a mile in his car and 9/10 of a mile in his truck. How far did Shane drive last week in all?
1/10 + 9/10 = 10/10 = 1
Shane drove 1 mile.
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Problem #3:
For a class experiment, Vina's class weighed a log before and after subjecting it to termites. Before subjecting it to termites, the log weighed 7/10 of a pound. After the termites, the log weighed 3/10 of a pound. How much weight did the termites take from the log?
7/10 - 3/10 = 4/10
The termites took 4/10 pound away from the log.
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Hope This Helps :)
