Answer:
p(x)= (x+1)(x+2)(x-3)(x-1)
then,multiplying two two terms
(x^2 +2x+x+2)(x^2-x-3x+3)
(x^2+3x+2)(x^2-4x+3)
x^4- 4x^3+3x^2 +3x^3-12x^2+9x+2x^2-8x+6)
x^4-x^3-7x^2+x+6
Explanation:
Vertex form of a quadratic function is given by y = a(x - h)² + k
where
1) 'a' determines if parabola is stretched or compressed.
If a > 1 then graph is stretched by a factor of a.
If 0 < a < 1, then graph is compressed by a factor of a.
2) If a > 0 then graph opens upwards with a happy face. (minimum)
3) If a < 0 then graph opens downwards with a sad face. (maximum)
4) (h, k) is the vertex point
5) The axis of symmetry is x = h
While solving for y = 1(x - 4)² + 3
Identify following's:
Vertex: (h, k) = (4, 3)
Axis of symmetry: x = 4
Max/Min: As here a > 0, Minimum (4, 3)
Stretch/compression: a = 1, the graph is stretched by a factor of 1.
Direction of opening: As a > 0, the graph opens upwards.
It is definitely (y-2)=3(x-2)
First, find the slope of the line using the formula for slope:
m = (y2 - y1) / (x2 - x1)
m = (4 - (-2)) / (-3 - 2) = -6/5
Then, use the point-slope formula using a point that you were given and the slope that you calculated.
y - y1 = m(x - x1)
y - 4 = (-6/5)(x + 3)
Then, simply get y alone.
y = (-6/5)x + 2/5