It equals to:
(3(a+h)^2 - 3a^2) / h = 3(2ah+h^2) / h = 6a + 3h
Answer:
If we have a set of N elements:
{x₁, x₂, ..., xₙ}
The mean value (also called the average value) Is calculated as:
Average = (x₁ + x₂ + ... + xₙ)/n
So if x is the average of 13, -16 and 6 ( a total of 3 values)
x will be equal to:
x = (13 + (-16) + 6)/3 = (19 - 16)/3 = 3/3 = 1
x = 1
And we know that:
y = ∛8
Remember that:
2*2 = 4
and
4*2 = 8
then
2*2*2 = 2^3 = 8
then ∛8 = 2.
So we have:
y = ∛8 = 2
Now we can replace these values in the equation:
x^2 + y^3
replacing:
x = 1
y = 2
we get:
1^2 + 2^3 = 1 + 8 = 9
Answer:
♀ I- I'm not sure how to explain
Answer:
{-3, 2}U{2, 5}
Step-by-step explanation:
For an equation to be negative, it would need to be in a negative range (below the x-axis or the coordinates are negative y-values). Therefore, we can examine this question and see that the graph is negative when the function crosses the x-axis at -3 and it remains negative until you reach 2 on the x-axis.
Therefore, the first set of negative values is (-3, 2).
Secondly, applying the same logic as before, the function decreases at 2 and then touches the x-axis again at 5. Therefore, the second negative value would be (2, 5).
The negative values are {-3, 2}U{2, 5}.
