Answer:
Part a) 
Part b) 
Step-by-step explanation:
Part a) we know that
The area of the shaded figure is equal to the area of semicircle plus the area of a triangle
<em>Find the area of semicircle</em>
The area of a semicircle is equal to

we have

substitute

<em>Find the area of triangle</em>
The area of the triangle is equal to

we have

-----> the height of triangle is equal to the diameter of semicircle
substitute

<em>Find the area of the shaded figure</em>

assume


Part b) we know that
The area of the shaded figure is equal to the area of the triangle minus the area of the circle
<em>Find the area of the circle</em>
The area of the circle is equal to

we have

substitute

<em>Find the area of triangle</em>
The area of the triangle is equal to

we have

substitute

<em>Find the area of the shaded figure</em>

assume


Answer: (7x^2+144)/x^2
Step-by-step explanation:
f(h(x))=
f(12/x)=
(12/x)^2+7=
12^2/x^2 + 7=
144/x^2 +7=
144/x^2 +7*x^2/x^2=
144/x^2+7x^2/x^2=(7x^2+144)/x^2
Hi
QPR = 74 (vertically opposite angles)according to angle sum property which means if we add all the angles of triangle we get 180 degrees
So,
PQR=180-(74+51)
180-125=55
So answer is 55 degrees