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How many grams are in 4 moles of aluminum phosphate

vladimir2022 [97]

Answer:

487.8116

Explanation:

4 0

4 years ago

Read 2 more answers

What is the purpose of writing Shorthand Electron Configuration Using Noble Gases?

stepan [7]

Noble gas electron configurations are easier to write because they are shorter then full electron configurations. They Noble gas shortcut electron configuration is a way of summarizing the information about the electrons of an atom.

(this is what I used)

6 0

3 years ago

12. How many moles of atoms are present in 154 g of Na2O?

tia_tia [17]

Answer:

$\boxed {\boxed {\sf A. \ 2.48 \ mol \ Na_2O}}$

Explanation:

We are asked to convert an amount in grams to moles. To do this, we use the molar mass. This is the number of grams in one mole of a substance. It is the same value numerically as the atomic mass on the Periodic Table, however the units are grams per mole, not atomic mass units.

Look up the molar masses for the individual elements.

Sodium (Na): 22.9897693 g/mol
Oxygen (O): 15.999 g/mol

Look back at the formula: Na₂O. Notice there is a subscript of 2 after sodium. This means there are 2 atoms of sodium in every molecule, so we have to multiply sodium's molar mass by 2 before adding oxygen's.

Na₂O: 2(22.9897693 g/mol)+ 15.999 g/mol = 61.9785386 g/mol

Set up a ratio using the molar mass.

$\frac {61.9785386 \ g \ Na_2O}{1 \ mol \ Na_2O}$

Multiply by the given number of grams.

$154 \ g \ Na_2O*\frac {61.9785386 \ g \ Na_2O}{1 \ mol \ Na_2O}$

Flip the ratio so the grams of sodium oxide can cancel each other out.

$154 \ g \ Na_2O*\frac {1 \ mol \ Na_2O}{61.9785386 \ g \ Na_2O}$

$154 *\frac {1 \ mol \ Na_2O}{61.9785386 }$

$\frac {154}{61.9785386 } \ mol \ Na_2O$

$2.48473106141 \ mol \ Na_2O$

The original measurement of grams given has 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place.

2.48473106141

The 4 in the thousandth place tells us to leave the 8.

$2.48 \ mol \ Na_2O$

There are 2.48 moles of sodium oxide in 154 grams, so choice A is correct.

6 0

3 years ago

If 8.2 L of hydrogen gas at STP are produced in this reaction, how many atoms of sodium react?

kati45 [8]

The reaction is;

2Na + 2H2O → 2NaOH + H2

Answer:

4.4 × 10^(23) atoms

Explanation:

The reaction is;

2Na + 2H2O → 2NaOH + H2

2 moles of Na produces 1 mole of H2 from the equation reaction.

Thus, since 8.2 L of hydrogen gas at STP are produced. And we know that at STP, 1 mole of a gas will have a volume of 22.4 L, and also, We know according to avogadro's number that, 1 mol = 6.02 × 10^(23) atoms, Thus;

8.2 L of H2 × (1 mole of H2/22.4 L) × (2 mole of Na/1 mole of H2) × (6.02 × 10^(23) atoms/1 mole of Na) = 4.4 × 10^(23) atoms

5 0

3 years ago

The starting substanceses of a chemical reaction are refered to as

Debora [2.8K]

The starting substances in a chemical reaction are called reactants - they are written on the left side of a chemical equation.

6 0

4 years ago