N2O = 28 + 16 = 44g
number of moles
= given mass/molar mass
= 0.173/44
= 0.0039318
81.9 % is the percent yield of reaction of zinc with iodine producing ZnI2.
Explanation:
Balanced chemical equation for the reaction:
Zn + I2 ⇒ ZnI2
Data given:
mass of sample zinc = 129 grams
mass of ZnI2 formed = 510.6 grams (actual yield)
number of moles = 
number of moles of zinc = 
= 1.97 moles
from stoichiometry
1 mole of Zn reacts to form 1 mole of ZnI2
1.97 moles of Zn will form 1.97 moles of ZnI2
atomic mass of ZnI2 = 319.22 grams/mole
mass of ZnI2 formed = 628.86 grams (theoretical yield)
% yield =
x100 equation 1
from the reaction,
Putting the values in equation 1
% yield =
x 100
= 81.19 % is the % yield.
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