Elements listed in vertical columns of the periodic table:

Chemistry

2 answers:

True [87]3 years ago

6 0

Answer: Option (a) is the correct answer.

Explanation:

It is known that chemical properties of an atom depends on the number of electrons in its outermost shell, that is, valence shell.

For example, Na has 1 electrons in its valence shell and K also has 1 valence electron as both Na and K belongs to the same group.

Therefore, vertical columns in the periodic table represent groups and horizontal lines represent period.

Thus, we can conclude that elements listed in vertical columns of the periodic table have similar chemical properties.

marysya [2.9K]3 years ago

3 0

Vertical columns are called groups, or families.

They share similar chemical properties.

Answer: have similar chemical properties

You might be interested in

Boron’s chemistry is not typical of its group.(a) Cite three ways in which boron and its compounds differ significantly from the

Mila [183]

Boron’s chemistry is not typical of its group. is group 3A (13) shows the increasing metallic character from Al to Tl.

All Boron compounds are covalent whereas the other elements in group 3A (13) form mostly ionic compounds.

Except for Boron, the other elements of group 3A (13) show increasing metallic character from Al to Tl. But Boron is a metalloid.

Compared to the other elements in group 3A, boron has a lower reactivity in chemical terms (13)

The metalloid boron (B), as well as the metals aluminium (Al), gallium (Ga), indium (In), and thallium, are all part of group 3A (or IIIA) of the periodic table (Tl). In contrast to the other members of Group 3A, the element borax primarily forms covalent connections.

To learn more about group 3A (13) refer the link:

brainly.com/question/5489194

#SPJ4

6 0

1 year ago

Need help asap please!

Andrei [34K]

Answer:

Explanation:

because polarity of the water molecules is due to the B. deflection of the hydrogen atoms by the lone pair of electrons.

4 0

3 years ago

When a 10 mL graduated cylinder is filled to the 10 mL mark, the mass of the water was measured to be 9.925 g. If the density of

Vlada [557]

Measured volume = 10 ml
mass = 9.925 g
density = 0.9975 g/ml
density = $\frac{mass}{volume}$
so actual volume = $\frac{mass}{density}$ = $\frac{9.925}{0.9975}$ = 9.95 mL
Percentage Error = $\frac{measured volume - Actual volume}{actual volume}$ x 100
= $\frac{10 - 9.95}{9.95}$ x 100 = 0.5 % error