Answer:
The answer is
Explanation:
The energy of a quantum of light can be found by using the formula
<h3>E = hf</h3>
where
E is the energy
f is the frequency
h is the Planck's constant which is
6.626 × 10-³⁴ Js
From the question
f = 4.31 × 10¹⁴ Hz
We have
E = 4.31 × 10¹⁴ × 6.626 × 10-³⁴
We have the final answer as
Hope this helps you
The oxidation number sulfur in H₂S is -2.
A compound's total number of oxidations must be zero.
The two hydrogen atoms in the chemical hydrogen sulfide, H₂S, each have an oxidation number of +1, making a total of +2. As a result, the compound's sulfur has an oxidation number of -2, and the total number of oxidations is 0.
Assume that the sulfur atom in H₂S has an oxidation number of x.
S be x.
Now,
2+x=0
⇒x=−2
<h3>What is oxidation number?</h3>
The total number of electrons that an atom either receives or loses in order to create a chemical connection with another atom is known as the oxidation number, also known as the oxidation state.
Depending on whether we are taking into account the electronegativity of the atoms or not, these phrases can occasionally have a distinct meaning. Coordination chemistry commonly makes use of the phrase "oxidation number."
<h3>What distinguishes an oxidation number from an oxidation state?</h3>
In contrast to the oxidation state, which indicates how oxidised an atom is in a molecule, the oxidation number describes the charge that the core metal atom will retain once all ligands have been removed.
To know more about oxidation number:
brainly.com/question/13182308
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Answer:
since the moisture in the bottle from the water collects smoke particles which form into clouds
Explanation:
Answer:
% purity of limestone = 96.53%
Explanation:
Question (4).
Weight of impure CaCO₃ = 25.9 g
Molecular weight of CaCO₃ = 40 + 12 + 3(16)
= 100 g per mole
We know at S.T.P. number of moles of CO₂ = 1 and volume = 22.4 liters
From the given reaction, 1 mole of CaCO₃ reacts with 1 mole or 22.4 liters of
CO₂.
∵ 22.4 liters of CO₂ was produced from CaCO3 = 100 g
∴ 1 liter of CO₂ will be produced by CaCO₃ = 
∴ 5.6 liters of CO₂ will be produced by CaCO₃ = 
= 25 g
Therefore, % purity of CaCO₃ = 
= 
= 96.53 %
