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3 years ago

What is the least common multiple (LMC) of 8 and 12?

1 answer:

3 0

Hey There!

If i am doing this the least common multiple can either be
2 or 4.
thus being
2, 4, 6, 8, 10, 12
Or
4, 8, 12.

Hope This Helps!!!

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Devide X^3+x^2+3x-4 by x^2+2x+1

lyudmila [28]

Answer:

x-1+\frac{4x-3}{x^2+2x+1}

Step-by-step explanation:

6 0

2 years ago

Which of the following is the solution to the equation x + 8.6 = 36.2?

zalisa [80]

We have that
x + 8.6 = 36.2
step 1

Subtract 8.6 both members
x+8.6-8.6=36.2-8.6
x=27.6

the answer is
the solution is x=27.6

3 0

2 years ago

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Which of the following are dependent events?

kotykmax [81]

The best answer is B im sorry if its wrong but im sure its B

4 0

2 years ago

Simplify: [5×(25)^n+1 - 25 × (5)^2n]/[5×(5)^2n+3 - (25)^n+1]

blagie [28]

$\green{\large\underline{\sf{Solution-}}}$

Given expression is 

$\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} }$

can be rewritten as

$\rm \: = \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\$

And

$\purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\$

So, using this identity, we

$\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} }$

can be further rewritten as

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)}$

$\rm \: = \: \dfrac{4}{25 - 1}$

$\rm \: = \: \dfrac{4}{24}$

$\rm \: = \: \dfrac{1}{6}$

Hence, 

$\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}$

3 0

2 years ago

I need help with this question on my math test

Salsk061 [2.6K]

Answer:

It still cannot be reached :( please send a photo.

5 0

2 years ago

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