You need more information to answer this question. Is there a table or percentage for that age group?
Answer:
0.053
Step-by-step explanation:
This is a geometric distribution problem.
I'm geometric distribution problem,
E(X) = 1/p
Where;
E(X) is expected value and p is probability of success
Thus;
1/p = 12.5
p = 1/12.5
p = 0.08
Now, to find the probability that the sixth person tested is the first one with high blood pressure, we will use the probability formula in geometric distribution which is;
P(X = k) = qⁿ•p
q = 1 - p
q = 1 - 0.08
q = 0.92
Thus;probability that the sixth person tested is the first one with high blood pressure will be expressed as;
P(X > 5) = (0.92^(5)) × 0.08
P(X > 5) = 0.053
Hello from MrBillDoesMath!
Answer:
(x+2) ( x^2 + 3)
Discussion:
x^3 + 2x^2 + 3x + 6 =
(
x^3 + 2x^2) + (3x + 6) = => factor "x^2" from the first term; factor 3
from the second term
x^2( x + 2) + 3( x+2) = => factor (x+2) from each term
(x+2) ( x^2 + 3)
Thank you,
MrB
