What is the value of x in the solution to this system of equations?

The Davis family has five children and one dog. Claudia is 5 years older than Nicki. Nicki's twin brother, Hunter, is 12 years o

Juli2301 [7.4K]

Nicki:x (12)
Claudia:x+5
Hunter:12
Decade=10 years
Dog: x-10
Philip:(x-10)+3=x-7
Sara: x-8
Sara:4

5 0

3 years ago

Please answer the following??????/

valentinak56 [21]

Answer:

I would be 3 8/10

Step-by-step explanation:

hope this helps

8 0

2 years ago

The amount of toothpaste in a tube is normally distributed with a mean of 6.5 ounces and a standard

Anarel [89]

Answer:

a) 266 tubes , TC_r = $53.2

b) 266 tubes , T.Loss = $13.30

Step-by-step explanation:

Given:

- The sample size of tubes n = 1,000 tubes

- The mean of the sample u = 6.5 oz

- The standard deviation of the sample s.d = 0.8 oz

- Cost of manufacturing a tube C_t = 50 cents

- Cost of refilling a tube C_r = 20 cents

- Profit loss per tube Loss = 5 cents

Find:

a). How many tubes will be found to contain less than 6 ounces? In that case, what will be the total cost of the refill?

b) How many tubes will be found to contain more than 7 ounces? In that case, what will be the amount of profit lost?

Solution:

- First we will compute the probability of tube containing less than 6 oz.

- Declaring X : The amount of toothpaste.

Where, X ~ N ( 6.5 , 0.8 )

- We need to compute P ( X < 6 oz )?

Compute the Z-score value:

P ( X < 6 oz ) = P ( Z < (6 - 6.5) / 0.8 ) = P ( Z < -0.625 )

Use the Z table to find the probability:

P ( X < 6 oz ) = P ( Z < -0.625 ) = 0.266

- The probability that it lies below 6 ounces. The total sample size is n = 1000.

The number of tubes with X < 6 ounces = 1000* P ( X < 6 oz )

= 1000*0.266 = 266 tubes.

- The total cost of refill:

TC_r = C_f*(number of tubes with X < 6)

TC_r = 20*266 = 5320 cents = $53.2

- We need to compute P ( X > 7 oz )?

Compute the Z-score value:

P ( X > 7 oz ) = P ( Z > (7 - 6.5) / 0.8 ) = P ( Z < 0.625 )

Use the Z table to find the probability:

P ( X > 7 oz ) = P ( Z > 0.625 ) = 0.266

- The probability that it lies above 7 ounces. The total sample size is n = 1000.

The number of tubes with X > 7 ounces = 1000* P ( X > 7 oz )

= 1000*0.266 = 266 tubes.

- The total cost of refill:

T.Loss = Loss*(number of tubes with X > 7)

T.Loss = 5*266 = 1330 cents = $13.30

5 0

2 years ago

Determine the quotient: 2 4/7 ÷ 1 3/6

Scilla [17]

First we must change these numbers to improper fractions:

$2\frac{4}{7}=\frac{18}{7}$

$1\frac{3}{6}=\frac{9}{6}$

So then we set it up:

$\frac{18}{7}$ ÷ $\frac{9}{6}$

When we divide fractions like this, we must flip the second fraction and change the sign from division to multiplication like so:

$\frac{18}{7}*\frac{6}{9}$

Then we solve:

$\frac{108}{63}$

Then if we divide the numerator and the denominator by 9, we get:

$\frac{12}{7}$ or, in mixed-number form, $1\frac{5}{7}$ .

4 0

3 years ago

A rolling pin has two identical cylindrical handles attached to a larger handle that is 12 inches long. The large cylinder measu

yaroslaw [1]

Answer:

Volume of the rolling pin = 246.09 $in^{3}$

Step-by-step explanation:

Length of larger cylinder L = 12 in

Diameter of larger cylinder D = 5 in

Diameter of two handles = 1.5 in

Length of two handles = 3 in

Volume of the rolling pin = Volume of two handles + Volume of larger cylinder

Volume of two handles = 2 ( $\pi r^{2}L$ )

Volume of two handles = 2 (3.14 × $0.75^{2}$ × 3 )

Volume of two handles = 10.59 $in^{3}$

Volume of larger cylinder = ( $\pi r^{2}L$ )

Volume of larger cylinder = (3.14 × $2.5^{2}$ × 12 )

Volume of larger cylinder = 235.5 $in^{3}$

Volume of the rolling pin = 10.59 + 235.5

Volume of the rolling pin = 246.09 $in^{3}$

6 0

2 years ago