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2 years ago

Find the sum of 0.333......and 0.444....

Mathematics

2 answers:

SashulF [63]2 years ago

7 0

Answer:

0.777......

Step-by-step explanation:

0.333...... + 0.444......

= 0.777......

Hope it helps :)

Please mark my answer as the brainliest

GarryVolchara [31]2 years ago

3 0

Step-by-step explanation:

The sum of 0.333.... and 0.444... is 0.777......

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For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les

kaheart [24]

Answer:

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

$\hat p=0.52$ estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

5 0

2 years ago

While walking in her neighborhood, Ashley found 3 dimes and 4 pennies on the ground. What percent of a dollar did Ashley find?

faltersainse [42]

Answer:

34%

Step-by-step explanation:

Dime = 10 cents, 10% of a dollar

Penny = 1 cent, 1% of a dollar

3 dimes = 30% of a dollar

4 pennies = 4% of a dollar

30% + 4% = 34%

3 0

3 years ago

3. Mr. James told Jill he would charge her $15 per hour, plus parts, to fix her bicycle.

ad-work [718]

Answer:

512

Solution:

so first you multiply 15 times 32 and get 480 than you add 32 and get 512.

7 0

2 years ago

The volume of a rectangular prism is given by the expression 2x^4+2x^3-4x^2-4x. Write the volume as the product its dimensions.

telo118 [61]

<h3>Answer: 2x(x^2-2)(x+1)</h3>

=========================================================

Explanation:

First factor out the GCF 2x

2x^4+2x^3-4x^2-4x

2x*x^3+2x*x^2-2x*2x-2x*2

2x(x^3 + x^2 - 2x - 2)

Then let's factor the expression inside the parenthesis using the factor by grouping method

x^3 + x^2 - 2x - 2

(x^3 + x^2) + (- 2x - 2)

x^2(x + 1) - 2(x + 1)

(x^2 - 2)(x+1)

We see that x^3 + x^2 - 2x - 2 factors to (x^2-2)(x+1)

Overall, the original expression fully factors to 2x(x^2-2)(x+1)

length = 2x

width = x^2-2

height = x+1

The order of length, width, and height doesn't matter.

7 0

2 years ago

Pls help me with this :)<br><br><br> .

san4es73 [151]

Answer:

35 is the answer thank u 35 is a real answer

3 0

3 years ago

Find the sum of 0.333......and 0.444....​

Find the sum of 0.333......and 0.444....