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3 years ago

Consider the rate law below.

Chemistry

2 answers:

katrin [286]3 years ago

7 0

D) The rate increases to eight times the original rate

Inessa [10]3 years ago

3 0

If you double the concentration of A, the rate is doubled. If you doubled the concentration of B, since the rate law has B^2, the rate is multiplied by 4. If you double both A & B's concentrations, then the rate would be multiplied by 2*4 = 8, which is the last option.

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For a particular reaction, Δ=−111.4 kJ and Δ=−25.0 J/K.

vichka [17]

Answer:

$\Delta G =-103.95kJ$

Explanation:

Hello there!

In this case, since the thermodynamic definition of the Gibbs free energy for a change process is:

$\Delta G =\Delta H-T\Delta S$

It is possible to plug in the given H, T and S with consistent units, to obtain the correct G as shown below:

$\Delta G =-111.4kJ-(298K)(-25.0\frac{J}{K}*\frac{1kJ}{1000J} )\\\\\Delta G =-103.95kJ$

Best regards!

6 0

3 years ago

Can the nature of a reactant be altered to speed up reaction

Step2247 [10]

Answer:

yeet

Explanation:

yeet

6 0

3 years ago

There have been different models of the atom over time. How has the competition between these models affected our understanding

lions [1.4K]

Doing the same final thanks

6 0

3 years ago

Read 2 more answers

What is the mole ratio needed to determine the mass of phosphorus trifluoride produced from the reaction of 120 g of phosphorus

Vitek1552 [10]

Answer:

$\frac{4molPF_3}{1molP_4}$

Explanation:

Hello

In this case, given the reaction:

$P_4(s)+6F_2(g)\rightarrow 4PF_3(g)$

It means that since the coefficients preceding phosphorous and phosphorous trifluoride are 1 and 4, the correct mole ratio should be:

$\frac{4molPF_3}{1molP_4}$

Because given the mass of phosphorous it is convenient to convert it to moles and then cancel it out with the moles on bottom of the mole ratio.

Bes regards!

8 0

2 years ago

Na2CrO4 + PbCL2<br> Formula in double replacement

Marta_Voda [28]

Na₂CrO₄ + PbCl₂ → PbCrO₄ + 2 NaCl

<u>Explanation:</u>

In a double displacement reaction, the reactants which are involved in the reaction exchanging their ions thereby produces 2 new compounds. Here sodium chromate and lead chloride are undergoing double displacement reaction, the ions exchanges their position there by forming sodium chloride and lead chromate. So the double displacement reaction is given as,

Na₂CrO₄ + PbCl₂ → PbCrO₄ + 2 NaCl

6 0

3 years ago