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zalisa [80]
3 years ago
12

Select the correct statement below:

Chemistry
1 answer:
uranmaximum [27]3 years ago
5 0

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

Valence electrons are defined as the electrons which are present in the outermost shell of the atom. Outermost shell has the highest value of 'n' that is principal quantum number.

For the given options:

  • <u>Option A:</u>

Phosphorus is the 15th element of the periodic table having electronic configuration 1s^22s^22p^63s^23p^3

Number of valence electrons = 2 + 3 = 5

The '3s' orbital is fully filled and all the three '3p' orbitals are half filled for the given element.

So, the given statement is not correct.

  • <u>Option B:</u>

Aluminium is the 13th element of the periodic table having electronic configuration 1s^22s^22p^63s^23p^1

Number of valence electrons = 2 + 1 = 3

The '3s' orbital is fully filled and one of all the three '3p' orbitals is half filled and rest are empty for the given element.

So, the given statement is not correct.

  • <u>Option C:</u>

Calcium is the 20th element of the periodic table having electronic configuration 1s^22s^22p^63s^23p^64s^2

Number of valence electrons = 2

The '4s' orbital is fully filled and all the three '4p' orbitals are half filled for the given element. '4s' sub-shell has only one orbital.

So, the given statement is not correct.

  • <u>Option D:</u>

Sodium is the 11th element of the periodic table having electronic configuration 1s^22s^22p^63s^1

Number of valence electrons = 1

The '3s' orbital is half filled and all the three '3p' orbitals are half filled for the given element.

So, the given statement is not correct.

Hence, the correct answer is Option D.

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How long does it take for a 12.62g sample of ammonia to heat from 209K to 367K if heated at a constant rate of 6.0kj/min? The me
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First, consider the steps to heat the sample from 209 K to 367K.

1) Heating in liquid state from 209 K to 239.82 K

2) Vaporaizing at 239.82 K

3) Heating in gaseous state from 239.82 K to 367 K.


Second, calculate the amount of heat required for each step.

1) Liquid heating

Ammonia = NH3 => molar mass = 14.0 g/mol + 3*1g/mol = 17g/mol

=> number of moles = 12.62 g / 17 g/mol = 0.742 mol

Heat1 = #moles * heat capacity * ΔT

Heat1 = 0.742 mol * 80.8 J/mol*K * (239.82K - 209K) = 1,847.77 J

2) Vaporization

Heat2 = # moles * H vap

Heat2 = 0.742 mol * 23.33 kJ/mol = 17.31 kJ = 17310 J

3) Vapor heating

Heat3 = #moles * heat capacity * ΔT

Heat3 = 0.742 mol * 35.06 J / (mol*K) * (367K - 239.82K) = 3,308.53 J

Third, add up the heats for every steps:

Total heat = 1,847.77 J + 17,310 J + 3,308.53 J = 22,466.3 J

Fourth, divide the total heat by the heat rate:

Time = 22,466.3 J / (6000.0 J/min) = 3.7 min

Answer: 3.7 min


3 0
3 years ago
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