Answer:
Explanation:
The moles of H2 and N2 are as follows respectively, 0.3915mol of H2 and 0.1305 mol of N2.
You just need to multiply the total mass by the decimal value of the part that is tin. 133.8*0.103=13.8g (following the rules of significant figures).
Answer:
2.77 mL of boiling water is the minimum amount which will dissolve 500 mg of phthalic acid.
Explanation:
We know from the problem that 18 g of phthalic acid are dissolved in 100 mL of water at 99 °C.
Now we devise the following reasoning:
If 18 g of phthalic acid are dissolved in 100 mL of water at 99 °C
Then 0.5 g of phthalic acid are dissolved in X mL of water at 99 °C
X = (0.5 × 100) / 18 = 2.77 mL of water
The volume of the water in cubic meter is determined as 3.2 x 10⁶ m³ .
<h3>Weight of one gallon of water</h3>
The weight of 1 gal of water is given as 3785 g
Mass of 8.48 x 10⁸ gal = 3785 x 8.48 x 10⁸ = 3.2 x 10¹² g
<h3>Volume of the water in cubic meters</h3>
Volume = mass/density
Volume = 3.2 x 10¹² g/1 gmL
Volume = 3.2 x 10¹² mL x 10⁻⁶ m³/mL = 3.2 x 10⁶ m³
Thus, the volume of the water in cubic meter is determined as 3.2 x 10⁶ m³ .
Learn more about volume here: brainly.com/question/1972490
#SPJ1
