Answer:
right now I can't tell you the answer but I can tell you that try to find the elements ,that have the same amount of those electrons
Explanation:
hope this helps it's what I can help you right now
It is 5n , that’s it the difference between the 10n and the 15 n
In No3-1 the oxidation number of oxygen is -5 so oxidation number of N would be +5
2 Li(s) +Cl₂→ 2 Li⁺ (aq) + 2Cl⁻ (aq)
The cell potential of the reaction above is +4.40V
<em><u>calculation</u></em>
Cell potential =∈° red - ∈° oxidation
in reaction above Li is oxidized from oxidation state 0 to +1 therefore the∈° oxid = -3.04
Cl is reduce from oxidation state 0 to -1 therefore the ∈°red = +1.36 V
cell potential is therefore = +1.36 v -- 3.04 = + 4.40 V
