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3 years ago

Antoine has 125 baseball cards. He has had 36 fewer cards than Antoine. How many baseball cards do they have in all?

Mathematics

2 answers:

Leviafan [203]3 years ago

8 0

Answer:

214

Step-by-step explanation:

subtract 125 and 36 you get 89 then add 125 by 89.hope this helped you

Naddik [55]3 years ago

6 0

Step-by-step explanation:

Antoine= 125 cards

Antoine2?= 125+36= 161 cards

Antoine + Antoine2= 125+161= 286 cards

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Mrs. Gilus is in charge of the budget for the school. Last year, we began the year with &708.88 in our bank account, but by

liberstina [14]

It sounds like they had $708.88 at the beginning, however by the end of the year they OWED $347.99. The first number is in the positive while the other is a negative. Add the last number to the first number for the amount that they have spent which would be $1,056.87.

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3 years ago

For the right triangle shown, the lengths of two sides are given. find the third side. leave your answer in simplified, radical

lisov135 [29]

If c is the hypotenuse and b is the leg, then the third side (a):
$a= \sqrt{c^2-b^2}= \sqrt{16^2-9^2}= \sqrt{256-81}= \sqrt{175}=5 \sqrt{7}$

If b and с are legs, then hypotenuse (a):
$a= \sqrt{b^2+c^2}= \sqrt{9^2+16^2}= \sqrt{81+256}= \sqrt{337}$

3 0

3 years ago

Read 2 more answers

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago

Evaluate the expression when x = 4 and y=-5.<br> -5y+x

Maru [420]

Answer:

$29$

Step-by-step explanation:

<u /> $-5y + x$

$-5(-5) + (4)$

$25 + 4$

$29$

Answer: $29$

8 0

3 years ago

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2. Bryan and Lori were each given the same pair of numbers. Bryan's description of the two numbers was: The larger number is 3 m

sleet_krkn [62]

Answer:

5 and 18

Step-by-step explanation:

The two numbers according to Bryan are x and 3x+3. According to Lori they are x and 5x-7. So we know that x+3x+3=x+5x-7. x and x cancel out. 3 and 7 add to 10. 5x-3x=2x. So 2x=10. X=5 and the other number is 18.

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3 years ago