The coordinates of a particle of water "t" seconds after it leaves the end of the fire hose will be
.. (x, y) = (38.4*cos(47.5°)t, -4.9t^2 +38.4*sin(47.5°)t)
Solving for t, we have
.. t = x/(38.4*cos(47.5°)
For x = 25.7 meters, t is about 0.99065 seconds.
Then y will be
.. -4.9*(0.99065)^2 +38.4*sin(47.5°)*0.99065 = 23.238 . . . . meters
The water will hit the building about 23.24 meters above the height of the hose.
Answer:
0.10s
Step-by-step explanation:
Given data
DIstance= 6.5ft
velocity = 64 feet per second
with the parameters given above, we can find the time taken as
velocity = distance/time
time= distance/velocity
time= 6.5/64
time= 0.10 seconds
Hence the time the ball took is 0.10s
Hope this helps!
Stay safe and have a great day :D
Answer: 12.56
Step-by-step explanation:
If I remember correctly, the equation for circumference is C=2r*pi (R representing radius). For this problem, if 2 is your radius 2R would equal 4. Take this number and multiply it by 3.14 (pi) to get your final answer.
