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djverab [1.8K]
3 years ago
5

Augustsky18; you there????? I lost my other account. NO ONE ELSE ANSWER THIS

Mathematics
1 answer:
balandron [24]3 years ago
3 0

Hey what happened? I was worried about you.

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If Lamar follows the pattern below how many tiles will he need for his seventh figure the top one
elena55 [62]
The answer is D) 64 tiles
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The difference between two times six and five
Effectus [21]

Answer:

The difference between 2 × 6 and 2 × 5 is ...

2 × 5  = 10

And,

2 × 6 = 12

So if you subtract 12 - 10

= 2

Therefor,  the difference is by 2

* Hopefully this helps:) Mark me the brainliest:)!!

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3 years ago
Will mark brainliest you don’t have to explain btw
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4 years ago
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The half-life of a radioactive kind of radium is 11 days. If you start with 72 grams of it, how
NISA [10]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of Radioactive decay.

N(t) = 72(1/2)^22/11

==> N(t) = 72 (1/2)^2

==> N(t) = 72/4

==> N(t) = 18 grams.

So the remaining would be 18 grams.

4 0
3 years ago
A code on a student ID card begins with 3 letters and ends with 5 digits. How many different ID codes are possible if…the letter
Scorpion4ik [409]

Answer:

The total number of combinations is 2,358,720,000

Step-by-step explanation:

For the letter part of the ID we have 3 letters out of a space of 26 possible letters (a-z), and they can't repeat. For the number part we want to group 5 numbers out of 10 possible algarisms (0-9).So we can make an arrangement for the letters and one for the numbers and multiply them. The arrangment can be done using the following formula:

A(n,k) = (n!)/(n-k)!

Where n is the total number of possibilities and k is the size of the group.

For the letters:

A(26,3) = (26!)/(26-3)! = (26!)/(23!) = (26*25*24*23!)/(23!) = 26*25*24 = 15600

For the numbers:

A(10,5) = (10!)/(10 - 5)! = 10!/5! = (10*9*8*7*6*5!)/(5!) = 10*9*8*7*6*5 = 151200

The total number of combinations is the product of both, so:

combinations = 15600*151200 = 2,358,720,000

4 0
3 years ago
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