sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
<u>Step-by-step explanation:</u>
We need to find sum of sequence : 46 + 42 + 38 + ... + (-446) + (-450)
Given sequence is an AP with following parameters as :

So , Let's calculate how many terms are there as :
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Sum of an AP is :
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Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
Let x be the first number each pair and y is the second of each
As you see 1x is 3y
And. 2x is 3*3y= 9y
3x = 3*3*3y= 27y
Last 4x =3*3*3*3y= 81y
So y = 3^x
Solution:
<u>Note that:</u>
- AB = EF
- BC = EG = 6x - 8
- 7x - 19 = 2x + 11
- Perimeter of triangle: 24 + 2x + 11 + 6x - 8
<u>Solving for x:</u>
- 7x - 19 = 2x + 11
- => 7x - 2x = 19 + 11
- => 5x = 30
- => x = 30/5 = 6
<u>Substitute the value of x into the expression (24 + 2x + 11 + 6x - 8): </u>
- 24 + 2x + 11 + 6x - 8
- => 24 + 2(6) + 11 + 6(6) - 8
- => 24 + 12 + 11 + 36 - 8
- => 24 + 12 + 3 + 36
- => 75 units
The perimeter of the triangle ABC is 75 units.
the answer is “c” i believe
Theyre all labeled correctly, what exactly is the question?