You need to put a photo of the shapes.
Answer:
x = 2, y = 1
Step-by-step explanation:
x + 4y = 6 and y = 3 - x have to be rearranged: x + 4y = 6 and x + y = 3
You subtract the equations to eliminate one of the variables (x) so that the other can be found
Team A) 45 people
Team B) 55 people
A)There are two ways to solve this problem, finding the number of combinations possible for Team B, or the number of combinations possible for Team A.
Team A
It's a given that 20 mathematicians are on team A, which leavs the other 25 people for team A to be chosen from a pool of 80 (100- 20 mathletes)
80-C-25 = 80! / (25!/(80-25)!) =<span>363,413,731,121,503,794,368
</span>or 3.63 x 10^20
Solving using Team B
Same concept, but choosing 55 from a pool of 80 (mathletes excluded)
80-C-25 = 80! / (55!(80-55!) = 363,413,731,121,503,794,368
or 3.63 x 10^20
As you can, we get the same answer for both.
B)
If none of the mathematicians are on team A, then we exclude the 20 and choose 45:
80-C-45 = 80! / (45!(80-45)!) = <span>5,790,061,984,745,3606,481,440
or 5.79 x 10^22
Note that, if you solve from the perspective of Team B (80-C-35), you get the same answer</span>
<h2>a) 16y</h2><h2>b) 8y</h2>
a) First, multiply the numbers 8 and 2, and we get 16.
Now, we have to multiply 16 and the algebraic notation “y”, we get the result of 16y.
<h3><u>
Whenever you multiply the number(s) with algebraic notations, you need to multiply the number(s) and write the algebraic notation at the end.</u></h3>
<u></u>
b) Multiply the number 8 and the algebraic notation “y”, and we get the result 8y.
<em>Hope this helps :)</em>
