The equation of the function g(x) is g(x) = x - 1
<h3>How to determine the
equation of the
function g(x)?</h3>
The given parameters are:
f(x) = x - 5
The above function f(x) is translated left by 4 units
So, we have
g(x) = f(x + 4)
This gives
f(x + 4) = x + 4- 5
Evaluate the sum
f(x + 4) = x - 1
So, we have:
g(x) = x - 1
Hence, the equation of the function g(x) is g(x) = x - 1
Read more about function transformation at:
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Z=0 I think it’s the answer
Answer:
84.5 m
Step-by-step explanation:
It is often helpful to draw a diagram for word problems involving geometric relationships. One for this problem is shown below.
The mnemonic SOH CAH TOA reminds you of the relationship between sides of a right triangle:
Tan = Opposite/Adjacent
Here we're given angles of depression measured from the horizontal (as shown in the diagram), but it is more convenient to use angles measured from the vertical. In particular, ∠BAO is the complement of 60°, and its tangent is the ratio OB/OA:
tan(30°) = OB/OA
OB = (200 m)·tan(30°) ≈ 115.47 m . . . . . . multiply by OA, use OA=200 m
Likewise, we have ...
OC = (200 m)·tan(45°) = 200 m
Then the width of the river is the difference between these values:
BC = OC -OB = 200 m - 115.47 m = 84.53 m
Hi, hope this helps you. Have a good day. :)
Answer:
A = $5,417.42 (balance of the account)
I = $2,617.42
Answer:
222 fence posts
Step-by-step explanation:
Since the log is 20 m long, correct to the nearest metre and has to be cut into fence posts which must be 90 cm long, correct to the nearest 10 centimetres, there can be x fence posts 90 cm long.
So, we have x × 90 cm = 20 m
x × 0.9 m = 20 m
x = 20 m/0.9 m
x = 222.22
x ≅ 222 fence posts
So, the largest number of fence posts that can possibly be cut from the log is 222 fence posts.