For the function shown below, find f(2): f(x)=2x^4-8x^2+5x-7

Need help for question number 1

amid [387]

Answer:

I believe that the answer is a

Step-by-step explanation:

tangent is

opposite/adjacent

5 0

3 years ago

Diego has 90 songs on his playlist. How may songs are there for each genre

miv72 [106K]

There aren’t enough components to answer this. How many generes are there? For example if there are 5 genres and the songs are evenly distributed, then there would be 18 songs because 90 divided by 5 is 18 but we only know there are 90 songs. I suppose the closest answer would be *90 divided by Y= X*

7 0

3 years ago

Read 2 more answers

Verify that each equation is an identity (1 - sin^(2)((x)/(2)))/(1+sin^(2)((x)/(2)))= (1+cosx)/(3-cosX)

Allisa [31]

Answer:

Given that we have;

$sin \left (\dfrac{x}{2} \right ) = \sqrt{\dfrac{1 - cos (x)}{2} }$

By the application of the law of indices and algebraic process of adding a and subtracting a fraction from a whole number, we have;

$\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( \dfrac{1 + cos (x)}{2} \right)}{\left (\dfrac{3 - cos (x)}{2} \right ) } =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}$

Step-by-step explanation:

An identity is a valid or true equation for all variable values

The given equation is presented as follows;

$\dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}$

From trigonometric identities, we have;

$sin \left (\dfrac{x}{2} \right ) = \sqrt{\dfrac{1 - cos (x)}{2} }$

$\therefore sin^2 \left (\dfrac{x}{2} \right ) = \dfrac{1 - cos (x)}{2}$

$1 - sin^2 \left (\dfrac{x}{2} \right ) = 1 - \dfrac{1 - cos (x)}{2} = \dfrac{2 - (1 - cos (x))}{2} = \dfrac{1 + cos (x))}{2}$

$1 + sin^2 \left (\dfrac{x}{2} \right ) = 1 + \dfrac{1 - cos (x)}{2} = \dfrac{2 + 1 - cos (x))}{2} = \dfrac{3 - cos (x))}{2}$

$\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( \dfrac{1 + cos (x)}{2} \right)}{\left (\dfrac{3 - cos (x)}{2} \right ) } =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}$

$\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}$

3 0

3 years ago

Write the equation of the line perpendicular to y=4/3x+1 that passes through the points (-8, 4).

Murrr4er [49]

Answer:

The equation is;

y = -3/4x + 12

Step-by-step explanation:

The general form for the equation of a straight line is;

y = mx + b

where m is the slope and b is the y-intercept

With respect to this question;

4/3 is the slope and 1 is the intercept

If two lines are perpendicular, then the product of their slopes is -1

Mathematically;

4/3 * m2 = -1

m2 = -3/4

So to find the equation of this second line, we use the point slope form

This is;

y-y1 = m(x-x1)

y-4 = -3/4(x + 8)

y- 4 = -3/4x + 8

y = -3/4x + 12

3 0

3 years ago

Find the coordinates of

antoniya [11.8K]

Answer:

B = (6, 4)

Step-by-step explanation:

You know that the midpoint is calculated as ...

M = (A +B)/2

Solving this for B, we find ...

2M = A + B

B = 2M - A

Filling in the coordinate values, we get ...

B = 2(5, -2) -(4, -8) = (2·5-4, 2(-2)+8)

B = (6, 4)

6 0

4 years ago