Answer:
<h3>D. A coal burning power plant</h3><h3 />
Explanation:
it is a coal power plant , nuclear power is economical and does not fluctuate as much as wind or solar power.
Unlike coal, it is considered clean in terms of the amount of greenhouse gas emissions produced by the power plant itself, although uranium mining and processing are not without risks and environmental impact
Answer:
303 Ω
Explanation:
Given
Represent the resistors with R1, R2 and RT
R1 = 633
RT = 205
Required
Determine R2
Since it's a parallel connection, it can be solved using.
1/Rt = 1/R1 + 1/R2
Substitute values for R1 and RT
1/205 = 1/633 + 1/R2
Collect Like Terms
1/R2 = 1/205 - 1/633
Take LCM
1/R2 = (633 - 205)/(205 * 633)
1/R2 = 428/129765
Take reciprocal of both sides
R2 = 129765/428
R2 = 303 --- approximated
Answer:
(d) 2.93 x 10⁻³ N
Explanation:
Given;
current in the wire, I = 11.4 A
angle of inclination, θ = 11.4⁰
magnetic field on the wire, B = 11. 4 x 10⁻³
length of the wire, L = 11.4 cm = 0.114 m
The magnitude of magnetic force on the wire is given by;
F = BILsinθ
F = (11.4 x 10⁻³)(11.4)(0.114)(sin 11.4°)
F = 0.00293 N
F = 2.93 x 10⁻³ N
Therefore, the correct option is "D"
Answer:
a) the final velocity is 35.75 ft/s
b) The final elevation is 45 ft
Explanation:
Given the data in the question;
Weight of object; W = 100 lbf
Change in kinetic energy; ΔE = 500 ft-lb
so
m - m = ΔE
m - m = 500
multiply both sides by 2
m - m = 1000
m( - ) = 1000
- = 1000/m
- = (1000)(g) / W
we know that, acceleration due to gravity g = 9.8 m/s² = 32.18 ft/s²
so we substitute
- = (1000)(32.18) / 100
- = (1000)(32.18) / 100
- = 32180 / 100
- = 321.8
since The initial velocity is given to be 40 ft/s;
(40)² - = 321.8
1600 - = 321.8
= 1600 - 321.8
= 1278.2
= √1278.2
= 35.75 ft/s
Therefore, the final velocity is 35.75 ft/s
b)
we know that;
change in potential energy is;
ΔP.E = mg( h - h )
given that; increase in potential energy; ΔP.E = 1500 ft-lbf
and mg = Weight = 100 lbf
we substitute
1500 = 100( h - h )
h - h = 1500 / 100
h - h = 15 ft
given that, elevation of the object; h = 30 ft
h - 30 ft = 15 ft
h = 15 ft + 30 ft
h = 45 ft
Therefore, The final elevation is 45 ft