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Anestetic [448]
3 years ago
5

What is the value of n in the equation below? a^n/a^3=a^9 3 6 12 27

Mathematics
1 answer:
noname [10]3 years ago
3 0
The answer is definitely 6
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HELP!!!!!!!!! I DONT UNDERSTAND THIS
ValentinkaMS [17]

Answer:

x=86^{\circ}

y=94^{\circ}

z=54^{\circ}

Step-by-step explanation:

First, let's look at the largest triangle (two smaller triangles are combined) to solve for z. Since the sum of the angles in a triangle adds up to 180^{\circ}, we can write the equation:

20+74+32+z=180

z=180-126

z=54^{\circ}

Looking at the smaller triangle on the left, y (exterior angle) is the sum of the two opposite interior angles of the triangle on the left:

y=74+20

=94^{\circ}

Since x is the exterior angle of the triangle on the right, it is equivalent to the sum of the opposite interior angles of that triangle:

x=32+z

=32+54

=86^{\circ}

Hope this helps :)

6 0
3 years ago
Help me with PART B!!! Use image to help!!
sasho [114]
I think it’s 3
i multiplied .2222 times 18
8 0
3 years ago
Identify intervals on which the function is increasing, decreasing, or constant.
tigry1 [53]
G ( x ) = 2 - ( x - 7 )²
g ( x ) = 2 - ( x² - 14 x + 49 )
g ( x ) = 2 - x² + 14 x - 49
g ( x ) = - x² + 14 x - 47
The maximum of the function is at:
x= - b / 2 a
x = - 14 / ( - 2 ) = 7
Therefore the function is increasing form x ∈ ( - ∞, 7 ) and decreasing for x ∈ ( 7, +∞ ).
Answer:
C.   increasing, x < 7; decreasing x > 7.
3 0
3 years ago
What is the measure of Angle R?
Ivanshal [37]

The sum of angles in triangle is equal to 180 degrees, so

<R =180-56-30

<R=94

8 0
4 years ago
Read 2 more answers
Use the quadratic formula to solve x2 + 2x - 120 = 0. Think about what other method could also be used to solve this equation. a
pshichka [43]

Answer:

x = 10 , -12

Step-by-step explanation:

Solution:-

- The given quadratic equation is to be solved using the quadratic formula. The general form of a quadratic equation is:

                           ax^2 + bx + c =0  

Where, [ a , b and c are constants ]

- The quadratic formula is given as:

                       

                           x = \frac{-b+/-\sqrt{b^2 - 4*a*c} }{2a}

- The given equation is:

                             x^2 + 2x - 120 = 0

Where, a = 1 , b = 2 , c = -120

- Solve using quadratic formula:

                       x = \frac{-2+/-\sqrt{2^2 - 4*1*(-120)} }{2*1}\\\\x = \frac{-2+/-\sqrt{4 + 480} }{2}\\\\x = \frac{-2+/-(22) }{2}\\\\\\x = 10 , -12    

7 0
3 years ago
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