Answer:
3-3x and 3
Step-by-step explanation:
f(x) = 3x-3
g(x) = -x
g(f(x)) in your g(x) substitute x with f(x)
g( f(x) ) = g( 3x-3) = -(3x-3) = -3x+3
is the the second choice from top because -3x+3 is the same with 3 -3x
g(f(x)) =3-3x
g(f(0)) always work from inside first, so first find f(0) than g(f(0))
f(0) = f(x=0) = 3*0-3 = -3
Now we do the g(f(0)) = g( -3) is the same as
g(x) except that we substitute x for -3, g(x= -3) = -(-3) =3
g(f(0))=3
*an easier way to find the answer for the second problem would have been that we knew that f(g(x) ) = 3-3x so f(g(0)) =3-3*0 = 3
Answer:
Step-by-step explanation:
if point (x,y) is rotated 90 degrees, x becomes y and y becomes -x
for point (x,y) rotated 90 degrees it will become (y,-x)
This describes a parabolic path that starts at x=0 on a value of y = -5.1. That's when the rock is below ground in the hole. To find the answer we need to know the second x axis crossing. The first is when it is rising and reaches ground level, the second is after it peaks and falls back to the ground and lands. Using the quadratic formula I get the two zeros of this function to be about
x= 15.29, and 66.71. The rock then lands 66.71 feet from him horizontally.
It would be: 65 * 20%
= 65 * 0.20 [ 20% = 20/100 = 0.20 ]
= 13
In short, Your Answer would be 13
Hope this helps!
