Answer:
percent (%) of ancient prehistoric thinner than 3 is 0.0013
Step-by-step explanation:
Given data
mean = 5.1 millimeters (mm)
standard deviation = 0.7 mm
to find out
percent (%) of ancient prehistoric thinner than 3
solution
we have given mean and SD
so Z will be = x -mean / SD
Z = ( x - 5.1 ) / 0.7
so P( x < 3 ) = P ( (x - 5.1 ) / 0.7 < ( 3 - 5.1 ) / 0.7 )
P( Z = ( 3 - 5.1 ) / 1.5 )
P( Z = -3 ) = 0.0013
percent (%) of ancient prehistoric thinner than 3 is 0.0013
I think the answer to you question is 35 i might be wrong tho but it may work.
Answer:
The answer is D
Step-by-step explanation:
Answer:
42%
Step-by-step explanation:
The first step is to calculate the difference in the number of fishes from the beginning of the day to the end of the day.
90 -52
= 38 fishes
Therefore the percent decrease can be calculated as follows
= 38/90 × 100
= 0.422 × 100
= 42.2 %
= 42% ( to the nearest cent)
