<h3>
Answer:</h3>
A and C
<h3>
Step-by-step explanation:</h3>
Given:
-60x+32 = Qx+P
Find:
Which values of P and Q result in an equation with no solutions? Choose all answers that apply:
(Choice A) A Q=-60 P=60
(Choice B) B Q=32 P=60
(Choice C) C Q=-60 P=−32
(Choice D) D Q=32 P=−60
Solution:
The equation will have no solution if it reduces to ...
0 = (non-zero constant)
If we add 60x-32 to both sides, we get
0 = 60x +Qx + P-32
0 = (Q+60)x +(P-32)
The x-term must be zero, so Q+60 = 0, or Q = -60.
The constant term must be non-zero, so P-32 ≠0, or P ≠ 32.
The appropriate answer choices are those with Q=-60 and P≠32, A and C.
Well when you add up it is 7.5+36= 1,011
Answer:
25.5 mi
Step-by-step explanation:
12 22.5 X
Let X be the shortest distance we are trying to find.
a units 2 b units 2 c units 2
12 units 2 + (22.5)=c units 2
144+506.25=c units 2
650.25=c units 2
=c units 2
25.5
