Answer: -3 and 5
<u>Step-by-step explanation:</u>
Let x represent the 1st digit and y represent the 2nd digit. Then,
Eq 1: 2x + 3y = 9 → 3(2x + 3y = 9) → 6x + 9y = 27
Eq 2: 3x + 2y = 1 → -2(3x + 2y = 1) → <u>-6x - 4y = -2</u>
5y = 25
y = 5
Substitute y = 5 into either of the original equations to solve for x:
2x + 3y = 9
2x + 3(5) = 9
2x + 15 = 9
2x = -6
x = -3
Check (using the other original equation):
3x + 2y = 1
3(-3) + 2(5) = 1
-9 + 10 = 1
-1 = 1
Ok so we'll go ahead and solve for y first - we just need to get it alone on one side of the equal sign
Step 1: subtract 2x from each side
2x - 7y - 2x = 19 - 2x
This cancels out the 2x on the left, giving us
-7y = 19 - 2x
Step 2: divide both sides by -7
=
+
This gives us
y = -19/7 + 2x/7
That should be your answer for the first question. Now solving the next parts are easy. All you need to do is plug in x.
When x = -3
y = -19/7 + 2x/7
y = -19/7 + 2(-3)/7
y = -19/7 - 6/7
y = -25/7
When x = 0
y = -19/7 + 2x/7
y = -19/7 + 2(0)/7
y = -19/7
When x = 3
y = -19/7 + 2x/7
y = -19/7 + 2(3)/7
y = -19/7 + 6/7
y = -13/7
Hope that helps! Feel free to ask if I can help with anything else :)