( 2x + 5 ) + ( 3x - 7
2 answers:
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Answer:
Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box has largest volume.
Step-by-step explanation:
Given that,
A box is being created out of a 15 inches by 10 inches sheet of metal.
The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.
The length of the metal box be = (15-2x) inches.
The width of the metal box be =(10-2x) inches
The height of the metal box be =x inches
Then, the volume of the metal box= length×width×height
=(15-2x)(10-2x)x cubic inches
=(150x-50x²+4x³) cubic inches
∴ V= 4x³-50x²+15x
Differentiating with respect to x
V'=12x²-100x+15
Again differentiating with respect to x
V''=24x-100
For maximum or minimum value, V'=0
12x²-100x+15=0
Apply quadratic formula , here a=12, b= -100 and c=15
For x= 8.18, The value of (15-2x) and (10-2x) will negative.
∴x=0.1528 .
Now,
∴At x=0.1528 inch, the volume of the metal box will be maximum.
Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box has largest volume.
We are looking to figure out the size of m<CAB
Since line AB is parallel to the line CD, m<CAB corresponds to m<ECD which means the size of the angles equals
m<ECD can be found by using the fact that angles in a triangle add up to 180°,
hence, 180°-58°-43°=79°
The size of m<CAB is 79°
Since line AB is parallel to the line CD, m<CAB corresponds to m<ECD which means the size of the angles equals
m<ECD can be found by using the fact that angles in a triangle add up to 180°,
hence, 180°-58°-43°=79°
The size of m<CAB is 79°