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3 years ago

Given:<T~=<v;st||uv prove:tu||vw

Mathematics

1 answer:

aleksklad [387]3 years ago

8 0

Why be like this? Hm

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Jacob drives for 4 hours at 23 miles per hour. how far did he travel?

baherus [9]

This question is actually pretty simple! In one hour, you can go 23 miles. So just multiply 23 by four and you get... 92 miles in four hours!
Hope this helps! Have a great day!

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3 years ago

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Help me pls

marusya05 [52]

Answer:

the answer is 6

Step-by-step explanation:

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3 years ago

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Solve the following absolute value equation.

cestrela7 [59]

Answer:

x= 8

x= -8

Step-by-step explanation:

|x+1| /3 = 3

|x+1| = 9

|x| + |1| = 9

|x| = 8

x= 8

x= -8

4 0

2 years ago

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

3 years ago

The measure of<br> an exterior angle<br> of a regular<br> octagon is x + 10.<br> Find x.

elena-s [515]

Answer:

x = 35

Step-by-step explanation:

The sum of the exterior angles of a polygon = 360°

Then

1 exterior angle = 360° ÷ 8 = 45° , so

x + 10 = 45 ( subtract 10 from both sides )

x = 35

3 0

3 years ago

Given:<T~=<v;st||uv prove:tu||vw​

Given:<T~=<v;st||uv prove:tu||vw