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Likurg_2 [28]
3 years ago
8

PLEASE HELP!! WILL GIVE BRAINLIEST!!

Mathematics
1 answer:
Komok [63]3 years ago
5 0

Answer:

The number is 3.

Step-by-step explanation:

5x3=15+12=27

9x3=27

Hope this helps

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Differentiate between the vertical and horizontal asymptotes of the function.
Degger [83]

Answer:

vertical asymptotes at x=0

no horizontal asymtotes

Step-by-step explanation:

https://simplisico.com/share/q/OPlkHJgPrpb7WW56eMHXWLbG

7 0
4 years ago
Triangle ABC is an isosceles triangle in which side
Shkiper50 [21]

Answer:

Option B.

Step-by-step explanation:

Consider the below figure attached with this question.

It is given that triangle ABC is an isosceles triangle.

From the below figure it is clear that the vertices of triangle are A(-2,-4), B(2,-1) and C(3,-4).

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using this formula, we get

AB=\sqrt{(2-(-2))^2+(-1-(-4))^2}=\sqrt{16+9}=5

BC=\sqrt{(3-2)^2+(-4-(-1))^2}=\sqrt{1+9}=\sqrt{10}

AC=\sqrt{(3-(-2))^2+(-4-(-4))^2}=\sqrt{25}=5

Now,

Perimeter of triangle ABC = AB + BC + AC

                        =5+\sqrt{10}+5

                        =10+\sqrt{10}

So, perimeter of triangle ABC is 10+\sqrt{10} units.

Therefore, the correct option is B.

4 0
3 years ago
Read 2 more answers
By what number should 1 1/2 be divided to get 2/3 ? *
andrew-mc [135]

Answer:

1

Step-by-step explanation:

1) The equation is 1 1/2 ÷ x = 2/3

2) You can multiply 2/3 with 1 1/2 to get your answer

3) 2/3 × 1 1/2 = 1

Hope this helps!

4 0
3 years ago
Help me to solve tan^3 2x-3tan2x+2=0
Irina18 [472]
Here you are!!!!!!!!!

5 0
3 years ago
Read 2 more answers
A section of guttering can hold up to 20 litres of rainwater. The diameter is 11cm. Work out the length in metres.
m_a_m_a [10]

Answer:

2.1 m

Step-by-step explanation:

The gutter is in the shape of a cylinder.

Its volume is 20 liters and its diameter is 11 cm (0.11 m).

Its radius is half of its diameter => r = 0.055 m.

The volume in cubic metres:

1 litre = 0.001 cubic metres

20 litres = 20 * 0.001 = 0.02 cubic metres

The volume of a section of guttering is given as:

V = \pi r^2h

where h = length of the guttering

Therefore:

0.02 = \pi * 0.055^2 * h\\\\0.02 = 0.009503h\\\\h = 0.02 / 0.009503\\\\h = 2.10 m

The length of the section of guttering is 2.1 m long.

3 0
3 years ago
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