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scoundrel [369]
3 years ago
15

Judi is making a frame for a square painting. The square painting is 11 3/8 inches on each side. To make sure that she has enoug

h wood Judi wants to buy two extra inches of wood for each corner. How much wood shoul Judi buy?
Mathematics
1 answer:
dimulka [17.4K]3 years ago
5 0

Answer:

53\frac{1}{2}\ in

Step-by-step explanation:

we know that

The perimeter of a square is equal to

P=4a

where

a is the length side of the square

in this problem we have

a=11\frac{3}{8}\ in

convert to an improper fraction

11\frac{3}{8}\ in=\frac{11*8+3}{8}=\frac{91}{8}\ in

Find the perimeter of the square

P=4\frac{91}{8}=45.5\ in

Remember to adds two extra inches for each corner

so

The wood needed is  

45.5\ in+2*4\ in= 53.5\ in

convert to mixed number

53.5\ in=53\frac{1}{2}\ in

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A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w
melamori03 [73]

Answer:

The hypothesis is:

<em>H₀</em>: p_{X}-p_{Y}=0.

<em>Hₐ</em>: p_{X}-p_{Y}.

Step-by-step explanation:

Let <em>X</em> = number of men who exercise regularly and <em>Y</em> = number of women who exercise regularly.

The information provided is:

n_{X}=150\\X=88\\n_{Y}=200\\Y=130

Compute the sample proportion of men and women who exercise regularly as follows:

\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587

\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and \hat p_{X}=0.587.

The random variable <em>Y</em> also follows a Binomial distribution with parameters <em>n</em> = 200 and \hat p_{Y}=0.65.

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

\hat p=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

So, the sampling distribution of the proportion of men and women who exercise regularly follows a Normal distribution.

A two proportion <em>z</em>-test cab be performed to determine whether the proportion of women is more than men who exercise regularly.

The hypothesis for this test cab be defined as:

<em>H₀</em>: The proportion of women is same as men who exercise regularly, i.e. p_{X}-p_{Y}=0.

<em>Hₐ</em>: The proportion of women is more than men who exercise regularly, i.e. p_{X}-p_{Y}.

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3 years ago
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