Answer:
C. Precipitation of white bismuth hydroxide.
Explanation:
When aqueous ammonia is added to a solution that has Bi3+ and CU2+ cations, what we would have as a chemical result is the precipitation of white Bismuth hydroxide.
The chemical reaction for this can be written as,
Bi3+ + 2NH3 + 3H2O ⇌ Bi(OH)3(s) + 3NH4
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Answer:
When combined with Hubble's visible-light data, astronomers can ... Dark things absorb light, but this invisible stuff neither absorbs, nor ... Is dark matter made of still undiscovered tiny particles, as most physicists suppose?
Explanation:
Answer:
Explanation:
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In this case, since the precipitation of the lead iodide is related to the iodide ion in solution, if we make react lead (II) nitrate with an iodide-containing salt, a possible chemical reaction would be:
In such a way, since 15.71 mL of a 0.5770-M solution of lead (II) nitrate precipitates out lead (II) iodide, we can first compute the moles of lead (II) nitrate in the solution:
Next, since there is a 1:2 mole ratio between lead (II) nitrate and iodide ions, we compute the moles of those ions:
Finally, since the mixing of the two solutions produce a final volume of 40.71 mL (0.04071 L), the resulting concentration (molarity) of the iodide ions in the student's unknown turns out:
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Answer:
<u>Part -A</u>
The change in the entropy from largest to smallest is 3>2=4 >1 >5>6.
<u>Part-B</u>
Change in entropy over a complete cycle is 1 =2 = 3= 4 = 5 = 6
Explanation:
<u>Part -A</u>
The change in entropy for the reversible process that transfers the heat energy 'Q' at temperature 'T' is
1)
2)
3)
4)
5)
6)
Therefore, The change in the entropy from largest to smallest is 3>2=4 >1 >5>6.
<u>Part-B</u>
Initial and final states of complete cycle are equal. after complete the one cycle the system returns to the original state. So, the change in the entropy will be the zero
Therefore, Change in the overall cycle is 1 =2 = 3= 4 =5=6