She will have negative eight dollars. Thats all I can say
Answer:
Either, (9+√69)/6 or (9-√69)/6
Step wise:
3x²-9x+1=0-------------------(i)
comparing equation onw with (ax²+bx+c=0), we get,
a=3, b=-9, c=1
now,
using Quadratic Formula,
(-b±√b²-4ac)/2a=x
{-(-9)±√(-9)²-4.3.1}/2.3=x
(9±√81-12)/6=x
(9±√69)/6=x
Taking +(ve) sign Taking -(ve) sign
(9+√69)/6=0 (9-√69)/6=0
∴(9+√69)/6=0 ∴(9-√69)/6=0
[∵They cannot be further solved]
Answer:
C)h(x) = x-3
Step-by-step explanation:
To find the inverse of a function, switch the "x" and "y" values, then isolate for "x".
f(x) is the y value.
y = x + 3
x = y + 3 Switch x and y
x - 3 = y Subtract 3 from both sides to isolate
y = x - 3 Change back to function of h
h(x) = x - 3
Answer:
-37.5 m
Step-by-step explanation:
If we assume that "one full day" is 24 hours, then 15 hours represents the fraction 15/24 of a day. Since the drilling rate was constant, and was presumed to start from a height of 0, the height after 15 hours is that fraction of the day's work:
... (15/24)×(-60 m) = -37.5 m
Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have
f^(-1)(f(x)) = x
Differentiating with the chain rule gives
(f^(-1))'(f(x)) f'(x) = 1
so that
(f^(-1))'(f(x)) = 1/f'(x)
Let x = a; then
(f^(-1))'(f(a)) = 1/f'(a)
(f^(-1))'(b) = 1/f'(a)
In particular, we take a = 2 and b = 7; then
(f^(-1))'(7) = 1/f'(2) = 1/5
