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3 years ago

Plz help asap i need help plz

Mathematics

1 answer:

Anettt [7]3 years ago

5 0

The answer is A, 297. I spent 10 minutes on this trust me

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In 2014, Chile experienced an intense earthquake with a magnitude of 8.2 on the Richter scale. In 2010, Haiti also experienced a

serg [7]

Answer:

The intensity of the earthquake in Chile was about 16 times the intensity of the earthquake in Haiti.

Step-by-step explanation:

Given:

magnitude of earthquake in Chile = 8.2

magnitude of earthquake in Haiti = 7.0

To find:

Compare the intensities of the two earthquakes

Solution:

The magnitude R of earthquake is measured by R = log I

R is basically the magnitude on Richter scale

I is the intensity of shock wave

For Chile:

given magnitude R of earthquake in Chile = 8.2

R = log I

8.2 = log I

We know that:

$y = log a_{x}$ is equivalent to: $x = a^{y}$

$R = log I$

8.2 = log I becomes:

$I = 10^{8.2}$

So the intensity of the earthquake in Chile:

$I_{Chile} = 10^{8.2}$

For Haiti:

R = log I

7.0 = log I

We know that:

$y = log a_{x}$ is equivalent to: $x = a^{y}$

$R = log I$

7.0 = log I becomes:

$I = 10^{7.0}$

So the intensity of the earthquake in Haiti:

$I_{Haiti} = 10^{7}$

Compare the two intensities :

$\frac{I_{Chile} }{I_{Haiti} } }$

$= \frac{10^{8.2} }{10^{7} }$

= $10^{8.2-7.0}$

= $10^{1.2}$

= 15.848932

Round to the nearest whole number:

Hence former earthquake was 16 times as intense as the latter earthquake.

Another way to compare intensities:

Find the ratio of the intensities i.e. $\frac{I_{Chile} }{I_{Haiti} } }$

$log I_{Chile}$ - $log I_{Haiti}$ = 8.2 - 7.0

$log(\frac{I_{Chile} }{I_{Haiti} } })$ = 1.2

Convert this logarithmic equation to an exponential equation

$log(\frac{I_{Chile} }{I_{Haiti} } })$ = 1.2

$10^{1.2}$ = $\frac{I_{Chile} }{I_{Haiti} } }$

Hence

$\frac{I_{Chile} }{I_{Haiti} } }$ = 16

6 0

3 years ago

Apply the distributive property to: 2(6*+4)

riadik2000 [5.3K]

Step-by-step explanation:

12*+8

hope this help if u need anymore help just ask

6 0

3 years ago

Insert 6 arthematic mean between 5 and -9

astraxan [27]

Answer:

see explanation

Step-by-step explanation:

Consider 5 and - 9 to be terms in an arithmetic sequence and we require to find the 6 terms between them.

The n th term of an arithmetic sequence is

$a_{n}$ = a + (n - 1)d ← d is required

Here a = 5 and $a_{8}$ = - 9, hence

5 + 7d = - 9 ( subtract 5 from both terms )

7d = - 14 ( divide both sides by 7 )

d = - 2

---------------------------------------------------------

The terms in the sequence are

5, 5 - 2, 5 - 4, 5 - 6, 5 - 8, 5 - 10, 5 - 12, - 9 , that is

5, 3, 1, - 1, - 3, - 5, - 7, -9

With the 6 arithmetic means being

3, 1, - 1, - 3, - 5, - 7

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3 years ago

What is 70000 grams into kilograms

UkoKoshka [18]

Answer:

70 kg

Step-by-step explanation:

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4 years ago

How to solve for j -10=║j-7║

Aleksandr [31]

Answer:

No solutions.

Step-by-step explanation:

-10 = 7

No solutions

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3 years ago