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3 years ago

A ball accelerate downward at 9.8 m/s2 with 1.7 of force. What is the mass of the ball?

Physics

1 answer:

masya89 [10]3 years ago

5 0

Answer:

0.14 kg

Explanation:

m=F/a = (1.4N/9.8 m/s/s) =0.14 kg

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Why did one liter of have a greater mass than the other liter prepared by a different method

VikaD [51]

Maybe the water wasnt stable enough and probably couldnt read the water level correctly

4 0

3 years ago

Read 2 more answers

How should the student change the circuit to give negative values for current and

natulia [17]

Answer:

changing the polarity or direction of the battery changes the sign of the voltage and the current

Explanation:

The sign of current and voltage are due to established conventions.

The way that a DC circuit with negative current values is by changing the polarity of the power source or by inverting the battery, this creates that the electrons move in the opposite direction

Changing the battery also changes the direction of the power difference, since the potential from positive to negative, in most cases negative is assigned a potential of zero volts

In summary, changing the polarity or direction of the battery changes the sign of the voltage and the current

3 0

2 years ago

A 600 N force acts on an object with a mass of 50 kg. What is the resulting acceleration of the object?

DochEvi [55]

Answer:

<h3>The answer is 12 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

f is the force

m is the mass

From the question we have

$a = \frac{600}{50} = \frac{60}{5} \\$

We have the final answer as

Hope this helps you

4 0

3 years ago

Radar is used to determine distances to various objects by measuring the round-trip time for an echo from the object. (a) How fa

BartSMP [9]

Answer

given,

Echo time = t = 1000 s

speed = ?

$v = \dfrac{d}{t}$

a) speed of electromagnetic wave

$c = \dfrac{d}{t}$

wave travels Venus two time

$c = \dfrac{2d}{t}$

$d = \dfrac{ct}{2}$

$d = \dfrac{3 \times 10^8\times 1000}{2}$

d = 1.5 x 10¹¹ m

b) now, echo time

$c = \dfrac{2d}{t}$

$t = \dfrac{2d}{c}$

$t = \dfrac{2\times 75}{3 \times 10^8}$

t = 5 x 10⁻⁷ s

8 0

3 years ago

A carpenter builds an exterior house wall with a layer of wood 3.0 cm thick on the outside and a layer of Styrofoam insulation 2

Leno4ka [110]

Answer:

A. T=15.54 °C

B. Q/A= 0.119 W/m2

Explanation:

To solve this problem we need to use the Fourier's law for thermal conduction:

$Q= kA\frac{dT}{dx}$

Here, the rate of flow per square meter must be the same through the complete wall. Therefore, we can use it to find the temperature at the plane where the wood meets the Styrofoam as follows:

$\frac{Q}{A} =\frac{T_1-T_0}{d_w}k_w=\frac{T_2-T_1}{d_s}k_s\\T_1(\frac{k_w}{d_w}+\frac{k_s}{d_s})=T_2\frac{k_s}{d_s}+T_0\frac{k_w}{d_w}\\T_1=\frac{T_2\frac{k_s}{d_s}+T_0\frac{k_w}{d_w}}{\frac{k_w}{d_w}+\frac{k_s}{d_s}}\\T_1= 15.54 \°C$

Then, to find the rate of heat flow per square meter, we have:

$\frac{Q}{A}=\frac{T_1-T_0}{d_w}k_w=0.119 \frac{W}{m^2}\\\frac{Q}{A}=\frac{T_2-T_1}{d_s}k_s= 0.119 \frac{W}{m^2}$

$T_0: Temperature \ in \ the \ house\\T_1: Temperature \ at \ the \ plane \ between \ wood \ and \ styrofoam\\T_2: Temperature \ outside\\k_w: k \ for \ wood\\d_w: wood \ thickness\\k_s: k \ for \ styrofoam\\d_s: styrofoam \ thickness$

7 0

3 years ago