An atom that has 1.5x10^19 free electrons will have a negative charge since these free electrons carry a negative charge on them. <span>The </span>charge<span> of one </span>electron<span> is -1.6 X 10</span><span>-19</span><span> Coulombs. Hope this answers the question. Have a nice day. </span>
For this case we have that by definition, physical power refers to the amount of work done for a unit of time.
So:

Where:
W: It's the work
t: It's time
The power units are in 
So, according to the problem data we have:

Clearing the work of the formula:

Thus, the work is 1200 joules.
Answer:
Option C
The reason for that is that P-waves (primary waves) travel faster than S-waves (secondary waves).
If we call

the speed of the primary waves and

the speed of the secondary waves, and we call

the distance of the seismogram from the epicenter, we can write the time the two waves take to reach the seismogram as


So the lag time between the arrival of the P-waves and of the S-waves is

We see that this lag time is proportional to the distance S, therefore the larger the distance, the greater the lag time.
Answer:
The coefficient of friction causes the force on the object to be less than its initial reading on the spring scale.
Explanation:
Since the block reads 24.5 N before the block starts to move, this is its weight. Now, when the block starts to move at a constant velocity, it experiences a frictional force which is equal to the force with which the student pulls.
Now, since the velocity is constant so, there is no acceleration and thus, the net force is zero.
Let F = force applied and f = frictional force = μN = μW where μ = coefficient of friction and N = normal force. The normal force also equals the weight of the object W.
Now, since F - f = ma and a = 0 where a = acceleration and m = mass of block,
F - f = m(0) = 0
F - f = 0
F = f
Since the force applied equals the frictional force, we have that
F = μW and F = 23.7 N and W = 24.5 N
So, 23.7 N = μ(24.5 N)
μ = 23.7 N/24.5 N
μ = 0.97
Since μ = 0.97 < 1, the coefficient of friction causes the force on the object to be less than its initial reading on the spring scale.