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jasenka [17]
3 years ago
8

The gravitational force acting on a lead ball is much larger than that acting on a wooden ball of the same size. Which statement

is true about when they are dropped
Physics
1 answer:
user100 [1]3 years ago
6 0

Complete question is;

The gravitational force acting on a lead ball is much larger than that acting on a wooden ball of the same size. Which statement is true about when they are dropped?

A) The acceleration due to gravity is the same for both balls.

B) The lead ball’s acceleration due to gravity is larger than the wooden ball’s.

C) The lead ball’s acceleration due to gravity is less than the wooden ball’s.

Answer:

Option A) The acceleration due to gravity is the same for both balls.

Explanation:

Density of Lead is 11.34 g/cm³ while density of hard wood is around 1.3 g/cm³

Thus, it means lead is the heavier object when both have same masses.

We are told that the wood and lead both have same size but from the density given above, it's clear that the mass of the lead ball is more than that of the wooden ball and thus, the force from would be more for the lead ball than the wooden ball.

Now, If we were to measure the position of both balls when falling, we will observe that they do not fall fall with a constant speed. This is because they fall with a constant acceleration and as such the speed increases.

Therefore both balls will hit the ground at the same time because they both start from a position of rest and both will have the same acceleration.

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As you coast down a long hill on your bicycle, potential energy from your height is converted to kinetic energy as you and your bike are pulled downward by gravity along the slope of the hill. While there is air resistance and friction slowing you down by a little bit, your speed increases gradually until you apply the brakes, causing enough friction to slow yourself and the bike to a stop at the bottom

8 0
4 years ago
A block on a horizontal frictionless plane is attached to a spring, as shown below. The block oscillates along the x-axis with s
AleksandrR [38]

The question is about unclear since no picture provided. But from the question, it could be guessed that the box is moving back and forth on the frictionless plane at the amplitude of A in simple harmonic motion.

Answer:

D. At x=0, it's acceleration is at a maximum

Explanation:

As the box move forward, it reaches point A and than move backward. Theoretically, the box will move backwards, through its origin, to point -A and then going forward.

Point A is the maximum displacement of the box in this case. At this point, the box instantaneously stop to go backward. Therefore the velocity at that moment is zero.

From point -A, the box travel forward and keep building up speed due to the release in potential energy of the spring. And at point x=0, the velocity become maximum. After point x=0, the velocity of the box slows down due to the conversion of kinetic energy to potential energy of the spring. And as it reaches point A, it reaches zero velocity.

The same can be said as the box travels backward from point A to -A

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4 years ago
Help with this ASAP it’s due today
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3 years ago
ich of the following is not accurate when describing solids? A. The amount of pressure exerted by a solid is solely dependent on
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5 0
3 years ago
The conducting path between the right hand and the left hand can be modeled as a 9.0-cm-diameter, 140-cm-long cylinder. The aver
Crank

Answer:

The potential difference is 121.069 V

Solution:

As per the question:

Diameter of the cylinder, d = 9.0 cm = 0.09 m

Length of the cylinder, l = 40 cm = 1.4 m

Average Resistivity, \rho = 5.5\ \Omega-m

Current, I = 100 mA = 0.1 A

Now,

To calculate the potential difference between the hands:

Cross- sectional Area of the Cylinder, A = \pi (\frac{d}{2})^{2} = 6.36\times 10^{- 3}\ m^{2}

Resistivity is given by:

\rho = R\frac{A}{l}

R = \rho \frac{l}{A}

R = 5.5\times \frac{1.4}{6.36\times 10^{- 3}} = 1210.69\ \Omega

Now, using Ohm's Law:

V = IR

V = 0.1\times 1210.69 = 121.069\ V

4 0
4 years ago
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